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Olenka [21]
3 years ago
5

What is the value of x?

Mathematics
1 answer:
AlekseyPX3 years ago
3 0
The horizontal value in a pair of coordinates: how far along the point is. The X Coordinate is always written first in an ordered pair of coordinates (x,y), such as (12,5). In this example, the value "12" is the X Coordinate.
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NEED HELP ASAP!!
Solnce55 [7]

Answer:

Only Cory is correct

Step-by-step explanation:

The gravitational pull of the Earth on a person or object is given by Newton's law of gravitation as follows;

F =G\times \dfrac{M \cdot m}{r^{2}}

Where;

G = The universal gravitational constant

M = The mass of one object

m = The mass of the other object

r = The distance between the centers of the two objects

For the gravitational pull of the Earth on a person, when the person is standing on the Earth's surface, r = R = The radius of the Earth ≈ 6,371 km

Therefore, for an astronaut in the international Space Station, r = 6,800 km

The ratio of the gravitational pull on the surface of the Earth, F₁, and the gravitational pull on an astronaut at the international space station, F₂, is therefore given as follows;

\dfrac{F_1}{F_2} = \dfrac{ \dfrac{M \cdot m}{R^{2}}}{\dfrac{M \cdot m}{r^{2}}} = \dfrac{r^2}{R^2}  = \dfrac{(6,800 \ km)^2}{(6,371 \ km)^2} \approx  1.14

∴ F₁ ≈ 1.14 × F₂

F₂ ≈ 0.8778 × F₁

Therefore, the gravitational pull on the astronaut by virtue of the distance from the center of the Earth, F₂ is approximately 88% of the gravitational pull on a person of similar mass on Earth

However, the International Space Station is moving in its orbit around the Earth at an orbiting speed enough to prevent the Space Station from falling to the Earth such that the Space Station falls around the Earth because of the curved shape of the gravitational attraction, such that the astronaut are constantly falling (similar to falling from height) and appear not to experience gravity

Therefore, Cory is correct, the astronauts in the International Space Station, 6,800 km from the Earth's center, are not too far to experience gravity.

6 0
3 years ago
What are the solutions to the equation? x2(x+2)(x+6)=0 Enter your answers in the boxes. x = or x = or x =
Talja [164]

x^2(x+2)(x+6)=0\\\\x^2=0 \vee x+2=0 \vee x+6=0\\\\x=0 \vee x=-2 \vee x=-6

5 0
3 years ago
Read 2 more answers
How many times larger is the 5 in 528, 394 as in 352, 107?
seraphim [82]

Answer: B 10 Times large

Step-by-step explanation:The first 5 is 500,000 And the second 5 is 50,000

500,000÷ 50,000= 10

7 0
2 years ago
Determine the intervals on which the function is increasing, decreasing, and constant. (5 points)
TEA [102]
The one above the one you have now
4 0
3 years ago
Read 2 more answers
What is the depth of water in a tank with 300,000 gallons of water at 70F when the pressure gauge at the bottom of the tank read
chubhunter [2.5K]

Answer:

53.08 ft

Step-by-step explanation:

The pressure at the bottom of the tank, P = ρgh where ρ = density of water = 1000 kg/m³, g = acceleration due to gravity = 9.8 m/s² and h = depth of water in tank.

Since the pressure at the bottom of the tank, P = ρgh, making h subject of the formula, we have

h = P/ρg

Since P = 23 psig = 23 × 1 psig = 23 × 6894.76 Pa = 158579.48 Pa

Substituting the values of the other variables into h, we have

h = P/ρg

h = 158579.48 Pa/(1000 kg/m³ × 9.8 m/s²)

h = 158579.48 Pa/(9800 kg/m²s²)

h = 16.18 m

h = 16.18 × 1 m

h = 16.18 × 3.28 ft

h = 53.08 ft

8 0
2 years ago
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