Question

Find the value of x and y. ( ANSWER NEEDS TO BE IN REDUCED RADICAL FORM )

Answer 1

Answer:

Part 1) $y=6\ units$

Part 2) $x=3\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

In the right triangle ABE

we have that

AE=BE

so

Is a 45°-90°-45° triangle

$cos(45\°)=\frac{\sqrt{2}}{2}$

$cos(45\°)=\frac{3\sqrt{2}}{y}$

so

$\frac{\sqrt{2}}{2}=\frac{3\sqrt{2}}{y}$

$y=6\ units$

In the right triangle EBC

we have that

Is a 45°-90°-45° triangle

$sin(45\°)=\frac{\sqrt{2}}{2}$

$sin(45\°)=\frac{x}{3\sqrt{2}}$

$\frac{x}{3\sqrt{2}}=\frac{\sqrt{2}}{2}$

$x=3\ units$