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aleksandrvk [35]
3 years ago
9

Find the value of x and y. ( ANSWER NEEDS TO BE IN REDUCED RADICAL FORM )

Mathematics
1 answer:
Vlada [557]3 years ago
8 0

Answer:

Part 1) y=6\ units

Part 2) x=3\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

In the right triangle ABE

we have that

AE=BE

so

Is a 45°-90°-45° triangle

cos(45\°)=\frac{\sqrt{2}}{2}

cos(45\°)=\frac{3\sqrt{2}}{y}

so

\frac{\sqrt{2}}{2}=\frac{3\sqrt{2}}{y}

y=6\ units

In the right triangle EBC

we have that

Is a 45°-90°-45° triangle

sin(45\°)=\frac{\sqrt{2}}{2}

sin(45\°)=\frac{x}{3\sqrt{2}}

\frac{x}{3\sqrt{2}}=\frac{\sqrt{2}}{2}

x=3\ units

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Calculate the distance between the points (-1, 3) and (4, -1).
BigorU [14]

The distance between those two points is 41 and in decimal form to the nearest tenth, that's 6.4

Explanation:

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Then we plug in our x's and y's:

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Then you simplify:

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5 0
3 years ago
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Write the log equation as an exponential equation. You do not need to solve for x.
V125BC [204]

Answer:

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7 0
3 years ago
In the diagram, the radius of the outer circle is
JulijaS [17]

the value of x is 8 cm.

<u>Step-by-step explanation:</u>

Correct Question : In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded region is 220π cm2. What is the value of x? Enter your answer in the box.

We have ,

the area of a circle =  πr²

the outer circle area = \pi(2x)^2 =4\pi x^2

the inside circle area = \pi (6)^2= 36\pi

According to Question,

the outer circle area - the inside circle area = he shaded region

⇒ \pi (4x^2)-36\pi =220\pi

⇒ x^2-9 =55

⇒ x^2=64

⇒x =\sqrt{64}=8

Therefore , the value of x is 8 cm.

5 0
3 years ago
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