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Brums [2.3K]
3 years ago
7

PLEASE HELP IT'S DUE IN 15 MINUTES!! WILL GIVE BRAINLIEST!!!!

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0
The answer would be 3x+2=10x-5
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A, B & C form a triangle where
rjkz [21]

Answer:

13.9mm

Step-by-step explanation:

short story, pythagorean theorem a²+b²=c²

a=13.5

b=3.2

c=?

13.5² = 182.25

3.2² = 10.24

c² = 192.49

c = 13.8740765458

round to 1 decimal place c = 13.9

3 0
3 years ago
What is the difference between 63 degree fahrenheit and negative 16 degrees fahrenheit
professor190 [17]
It is 63-(-16) or 63+16 which is 79. So the difference is 79 degrees Fahrenheit
8 0
3 years ago
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AleksAgata [21]
The plants will each get 1 1/15 cups of water
7 0
4 years ago
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How many 1/3 cubes does it take to fill a box with a width of 2 2/3 inches length 3 1/3 inches and height 2 1/3
Paladinen [302]

Answer:

560

Step-by-step explanation:

I assume 1/3 is the side length of the cubes.

There's two ways to solve this:

1. Find the volume of the box, then divide by the volume of the cubes.

Or 2. Find the number of cubes per each side length, the find the volume in terms of cubes.

Either way, we need to convert the mixed fractions to improper fractions.

W = 2⅔ = (2×3+2)/3 = 8/3 inches

L = 3⅓ = (3×3+1)/3 = 10/3 inches

H = 2⅓ = (2×3+1)/3 = 7/3 inches

Using the first method, the volume of the box is:

V = (8/3 in) (10/3 in) (7/3 in) = 560/27 in³

The volume of a cube is:

V = (1/3 in)³ = 1/27 in³

So the number of cubes in the box is:

(560/27 in³) / (1/27 in³) = 560

Using the second method, the cubes per each side of the box is:

W = (8/3 in) / (1/3 in) = 8

L = (10/3 in) / (1/3 in) = 10

H = (7/3 in) / (1/3 in) = 7

So the number of cubes is:

8 × 10 × 7 = 560

7 0
3 years ago
Which congruence theorem can be used to prove<br> ABR - ARCA?<br> OHL<br> O SSS<br> OASA<br> O SAS
REY [17]

Answer:

ASA

Step-by-step explanation:

Since there are 2 lines on the hypotenuse, it means that they are congruent. As well as the right angles, the other angles could be calculated.

8 0
3 years ago
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