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photoshop1234 [79]
3 years ago
11

Beth estimates her expenditures for transportation as follows: May, $91; June, $122; July $478. What is her estimated average mo

nthly expense for transportation?
Help please!
Mathematics
1 answer:
kipiarov [429]3 years ago
4 0

Answer:

around 230

Step-by-step explanation:

91+122+478=691

691÷3= 230.33333333

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Given below are some inequalities. Plot the feasible region graphically.
igor_vitrenko [27]

Answer:

0-89x=78/-43

Step-by-step explanation:

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3 years ago
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Express as a trinomial (3x+8) (x+10)
docker41 [41]

Answer:

3x^{2} +38x+80

Step-by-step explanation:

Hello!

A trinomial is a expression consisting of three different terms

To turn this into a trinomial we multiply everything to each other

<u>                     3x                     </u>

3x * x = 3x^{2}

3x * 10 = 30x

<u>                     8                      </u>

8 * x = 8x

8 * 10 = 80

Now we put them all together in an equation

3x^{2} +30x+8x+80

Combine like terms

3x^{2} +38x+80

The answer is 3x^{2} +38x+80

Hope this helps!

7 0
3 years ago
Can i get help with 4,6, and 8 PLEASE HELP!!!!!!!!!! IM GONNA RUN OUTTA TIME!!!!
gogolik [260]
They are all even numbers
8 0
3 years ago
Assume V and W are​ finite-dimensional vector spaces and T is a linear transformation from V to​ W, T: Upper V right arrow Upper
scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that  

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.  

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that  

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0  

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

8 0
2 years ago
No links please !!! :D
Vinil7 [7]

Answer:

The answer should be B. 86.7

6 0
2 years ago
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