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MissTica
3 years ago
15

Simplify the expression: -15/4 + 5/6

Mathematics
1 answer:
AleksandrR [38]3 years ago
6 0

Answer:

-35/12

Step-by-step explanation:

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The Clinton family is building a circular swimming pool. If the radius of the pool is 5 feet, what is its circumference? Use π =
densk [106]

Formula:2 pi R

R=5

5*2=10

3.14*10=34.1

The circumfrence is 34.1

34.1

6 0
3 years ago
You Want to save money for college. You have already saved $500, and you able save $75 each week that's how much you get in a we
marusya05 [52]
You can set up an equation for this. if x is the amount of weeks, and m is total money, then it'd be
500+75x=m
plug numbers in
3 weeks: 500+75*3=$725
10 weeks: 500+75*10=$1250
6 months, each month having 4 weeks, is 24 weeks
500+24*75=$2300

6 0
3 years ago
Read 2 more answers
Find the missing side lengths. Leave your answers as radicals in simplest form.
tankabanditka [31]

Answer:

A.

x = \frac{7\sqrt{6}{3}

y = \frac{7\sqrt{6}}{3}

Step-by-step explanation:

Reference angle = 60°

Opposite = \frac{7\sqrt{2}}{2}

Hypotenuse = x

Adjacent = y

✔️To find x, apply the trigonometric function SOH:

Sin 60° = Opp/Hyp

sin 60° = \frac{\frac{7\sqrt{2}}{2}}{x}

\frac{\sqrt{3}}{2} = \frac{\frac{7\sqrt{2}}{2}}{x} (sin 60 = √3/2)

\frac{\sqrt{3}}{2} = \frac{7\sqrt{2}}{2}*\frac{1}{x}

\frac{\sqrt{3}}{2} = \frac{7\sqrt{2}}{2x}

Cross multiply

\sqrt{3}*2x = 7\sqrt{2}*2

2\sqrt{3}*x = 14\sqrt{2}

Divide both sides by 2

\sqrt{3}*x = 7\sqrt{2}

Divide both sides by √3

x = \frac{7\sqrt{2}}{\sqrt{3}}

Rationalize

x = \frac{7\sqrt{2}*\sqrt{3}}{\sqrt{3}*\sqrt{3}}

x = \frac{7\sqrt{6}{3}

✔️To find y, apply the trigonometric function TOA:

Tan 60° = Opp/Adjacent

Tan 60° = \frac{\frac{7\sqrt{2}}{2}}{y}

\sqrt{3} = \frac{\frac{7\sqrt{2}}{2}}{y} (tan 60 = √3)

\sqrt{3} = \frac{7\sqrt{2}}{2}*\frac{1}{y}

\sqrt{3} = \frac{7\sqrt{2}}{2y}

Cross multiply

\sqrt{3}*2y = 7\sqrt{2}

2\sqrt{3}*y = 7\sqrt{2}

Divide both sides by √3

y = \frac{7\sqrt{2}}{\sqrt{3}}

Rationalize

y = \frac{7\sqrt{2}*\sqrt{3}}{\sqrt{3}*\sqrt{3}}

y = \frac{7\sqrt{6}}{3}

4 0
3 years ago
How do you answer this following equation “ the sum of two numbers is 33 , and the sum of 7 times the first number and 5 times t
nadya68 [22]

\bf \begin{cases} a\\\\ b \end{cases}\qquad \qquad \begin{array}{llll} \stackrel{\textit{the sum of \underline{a} and \underline{b}}}{a+b=33}\\\\ \stackrel{\textit{the sum of 7 times \underline{a} and 5 times \underline{b}}}{7a+5b=197} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a+b=33\implies \boxed{b}=33-a \\\\\\ \stackrel{\textit{substituting \boxed{b} in the second equation}}{7a+5\left(\boxed{33-a} \right)=197}\implies 7a+165-5a=197


\bf 2a+165=197\implies 2a=32\implies a=\cfrac{32}{2}\implies \blacktriangleright a=16 \blacktriangleleft \\\\\\ \boxed{b}=33-a\implies b=33-16\implies \blacktriangleright 17\blacktriangleleft

4 0
3 years ago
Can someone help me please!!
podryga [215]
I believe it is 3^2
8 0
4 years ago
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