Answer:
i think its D
f(x) = x-3 and g(x) = x+11
f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33
hope this helped :3
Answer:
Maximize C =


and x ≥ 0, y ≥ 0
Plot the lines on graph




So, boundary points of feasible region are (0,1.7) , (2.125,0) and (0,0)
Substitute the points in Maximize C
At (0,1.7)
Maximize C =
Maximize C =
At (2.125,0)
Maximize C =
Maximize C =
At (0,0)
Maximize C =
Maximize C =
So, Maximum value is attained at (2.125,0)
So, the optimal value of x is 2.125
The optimal value of y is 0
The maximum value of the objective function is 19.125
Answer:
2.34 grams
Step-by-step explanation:
In this problem, we need to find how many grams in 2.34mL. To solve the problem, we must know the relationship between grams and millilitre.
We know that,
1 milliitre = 1 gram
Hence,
2.34 mL = 2.34 grams.
Answer:
A. 24.5
Step-by-step explanation:
HOPE THIS HELPS!!!!
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