All categories

3 years ago

Can someone help me please!!

Mathematics

2 answers:

podryga [215]3 years ago

8 0

I believe it is 3^2

CaHeK987 [17]3 years ago

3 0

Omg so easy !

i believe the answer would be 3^1
have a nice day :)

You might be interested in

Find the function r that satisfies the given condition. r'(t) = (e^t, sin t, sec^2 t): r(0) = (2, 2, 2) r(t) = ()

lesantik [10]

Answer:

r(t) = (e^t +1, -cos(t) + 3, tan(t) + 2)

Step-by-step explanation:

A primitive of e^t is e^t+c, since r(0) has 2 in its first cooridnate, then

e^0+c = 2

1+c = 2

c = 1

Thus, the first coordinate of r(t) is e^t + 1.

A primitive of sin(t) is -cos(t) + c (remember that the derivate of cos(t) is -sin(t)). SInce r(0) in its second coordinate is 2, then

-cos(0)+c = 2

-1+c = 2

c = 3

Therefore, in the second coordinate r(t) is equal to -cos(t)+3.

Now, lets see the last coordinate.

A primitive of sec²(t) is tan(t)+c (you can check this by derivating tan(t) = sin(t)/cos(t) using the divition rule and the property that cos²(t)+sin²(t) = 1 for all t). Since in its third coordinate r(0) is also 2, then we have that

2 = tan(0)+c = sin(0)/cos(0) + c = 0/1 + c = 0

Thus, c = 2

As a consecuence, the third coordinate of r(t) is tan(t) + 2.

As a result, r(t) = (e^t +1, -cos(t) + 3, tan(t) + 2).

6 0

3 years ago

a 12-ft-long ladder is leaning against a building. the ladder makes a 45 degree angle with the building. how far up the building

zhuklara [117]

12 cos45degree=8.486 ft

6 0

3 years ago

I need help, Now please

Sav [38]

Answer
D

Explanation:

7 0

3 years ago

HELP HELP PLEASE!!! <3

zmey [24]

12 x 12 = 144, 144 x 3 and then subtract 5 to get 427

4 0

3 years ago

Read 2 more answers

Express the complex number in trigonometric form. 5 - 5i

bazaltina [42]

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Lets do this step by step.

This is the trigonometric form of a complex number where $|z|$ is the modulus and $0$ is the angle created on the complex plane.

$z = a + bi = |z| (cos ( 0 ) + I sin (0))$

The modulus of a complex number is the distance from the origin on the complex plane.

$|z| = \sqrt{a^2 + b^2}$ where $z = a + bi$

Substitute the actual values of a = -5 and b = -5.

$|z| = \sqrt{(-5) ^2 + (-5) ^2}$

Now Find $|z|$ .

Raise - 5 to the power of 2.

$|z| = \sqrt{25 + (-5) ^2}$

Raise - 5 to the power of 2.

$|z| = \sqrt{25 + 25}$

Add 25 and 25.

$|z| = \sqrt{50}$

Rewrite 50 as 5^2 . 2 .

$|z| = 5\sqrt{2}$

Pull terms out from under the radical.

$|z| = 5\sqrt{2}$

The angle of the point on the complex plane is the inverse tangent of the complex portion over the real portion.

$0 = arctan (\frac{-5}{-5} )$

Since inverse tangent of $\frac{-5}{-5}$ produces an angle in the third quadrant, the value of the angle is $\frac{5\pi }{4}$ .

$0 = \frac{5\pi }{4}$

Substitute the values of $0 = \frac{5\pi }{4}$ and $|z| = 5\sqrt{2}$ .

$5\sqrt{2} ( cos( \frac{5\pi}{4}) + i sin (\frac{5\pi}{4}))$

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

6 0

3 years ago

Read 2 more answers