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GenaCL600 [577]
3 years ago
12

Can someone help me please!!

Mathematics
2 answers:
podryga [215]3 years ago
8 0
I believe it is 3^2
CaHeK987 [17]3 years ago
3 0
Omg so easy ! 

i believe the answer would be 3^1  
have a nice day :)
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Find the volume of a square pyramid with a base area of 18inch squared and the height of 4 inches
den301095 [7]
Vpyramid=1/3 times area of base times height
volume=1/3 times 18 square inches times 4in
volume=6 square inches times 4in
volume=24 cubic inches


the volume is 24 cubic inches
5 0
3 years ago
Remy has a job at the local store. He spends $80 in a game parlor and $250 for food per month, and saves the rest of his salary.
Serga [27]
I think B would be the right answer
3 0
3 years ago
Read 2 more answers
You need 20 pounds of grass seed to plant grass inside the baseball diamond below. About how many pounds of grass seed
taurus [48]

Answer:

13 pounds of grass.

Step-by-step explanation:

You need 20 pounds of grass seed to plant inside the baseball diamond.

The Baseball Diamond is a square of side = 90 ft

The Softball Diamond is a square of side = 60 ft

The ratio of the size of the Baseball Diamond to that of Softball Diamond is:

90: 60 = 3:2

If 3 represents 20 pounds, then 2 represents;

\frac{2}{3} × 20 = 13.33333333 pounds = 13 pounds (rounded to nearest pound)

6 0
3 years ago
Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1
Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

        P.Q. = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean = 101

              \sigma = population standard deviation

              n = sample size = 25

So, 90% confidence interval for the population mean test score, \mu is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.6449) = 0.90

P(-1.6449 * \frac{\sigma}{\sqrt{n} } < {Xbar-\mu} < 1.6449 * \frac{\sigma}{\sqrt{n} } ) = 0.90

P(X bar - 1.6449 * \frac{\sigma}{\sqrt{n} } < \mu < X bar + 1.6449 * \frac{\sigma}{\sqrt{n} } ) = 0.90

90% confidence interval for \mu = [ X bar - 1.6449 * \frac{\sigma}{\sqrt{n} } , X bar + 1.6449 * \frac{\sigma}{\sqrt{n} } ]

                                                  = [ 101 - 1.6449 * \frac{17}{\sqrt{25} } , 10 + 1.6449 * \frac{17}{\sqrt{25} } ]

                                                  = [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0
3 years ago
Don't need an answer anymore :[
sergeinik [125]

Answer:

why.

what question was it

5 0
3 years ago
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