Answer: After washing 20 cars together, each team will have raised the same amount in total.
Step-by-step explanation:
Let x represent the number of cars that each each teams will wash for them to raise the same amount in total.
The volleyball team gets $4 per car. In addition, they have already brought in $24 from past fundraisers. This means that the total amount raised by the volleyball team after washing x cars would be
4x + 24
The wrestling team has raised $84 in the past, and they are making $1 per car today. This means that the total amount raised by the wrestling team after washing x cars would be
x + 84
For both amounts to be equal, the number of cars would be
4x + 24 = x + 84
4x - x = 84 - 24
3x = 60
x = 60/3
x = 20
D. x=3
I don't really know how to explain it other than the only points on the line are sitting at the x=3 and y=anything
If all the power of the variables are greater than or equal to zero, then the expression is a valid polynomial.
So,
1.



are polynomials.
2.

y
2 + s

are all polynomials.
3.
If the degree of the polynomial is 3, then it is a cubic polynomial. If the number of terms of a polynomial is 3, then it is a trinomial.
Hence,
is a cubic trinomial.
4.
The highest power is the degree.
Hence, degree of the polynomial is 2 + 4 = 6.
First of all, when I do all the math on this, I get the coordinates for the max point to be (1/3, 14/27). But anyway, we need to find the derivative to see where those values fall in a table of intervals where the function is increasing or decreasing. The first derivative of the function is

. Set the derivative equal to 0 and factor to find the critical numbers.

, so x = -3 and x = 1/3. We set up a table of intervals using those critical numbers, test a value within each interval, and the resulting sign, positive or negative, tells us where the function is increasing or decreasing. From there we will look at our points to determine which fall into the "decreasing" category. Our intervals will be -∞<x<-3, -3<x<1/3, 1/3<x<∞. In the first interval test -4. f'(-4)=-13; therefore, the function is decreasing on this interval. In the second interval test 0. f'(0)=3; therefore, the function is increasing on this interval. In the third interval test 1. f'(1)=-8; therefore, the function is decreasing on this interval. In order to determine where our points in question fall, look to the x value. The ones that fall into the "decreasing" category are (2, -18), (1, -2), and (-4, -12). The point (-3, -18) is already a min value.