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ella [17]
3 years ago
5

Three beads are placed on the vertices of an equilateral triangle of side d = 3.6 cm. The first bead of mass m1 = 130 g is place

d on the top vertex. The second bead of mass m2 = 55 g is placed on the left vertex. The third bead of mass m3 = 95 g is placed on the right vertex. show answer No Attempt 25% Part (a) Write a symbolic equation for the horizontal component of the center of mass relative to the left vertex of the triangle.
Mathematics
1 answer:
lara [203]3 years ago
4 0

Answer:

a) \bar x = \frac{d\cdot m_{3}+(d\cdot \cos 60^{\textdegree})\cdot m_{1}}{m_{1}+m_{2}+m_{3}}

Step-by-step explanation:

a) Let be origin set in the left vertex of the triangle and the horizontal axis is parallel to the side between the right and left beads. The horizontal component of the center of mass is:

\bar x = \frac{d\cdot m_{3}+(d\cdot \cos 60^{\textdegree})\cdot m_{1}}{m_{1}+m_{2}+m_{3}}

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Zepler [3.9K]

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alexgriva [62]

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8

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(

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(

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(

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−

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x

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−

10

x

2

(

2

x

)

(

6

)

=

12

x

(

3

)

(

4

x

2

)

=

12

x

2

(

3

)

(

−

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=

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15

x

(

3

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(

6

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And now we add them all up (I'm going to group terms in the adding):

8

x

3

−

10

x

2

+

12

x

2

+

12

x

−

15

x

+

18

And now simplify:

8

x

3

+

2

x

2

−

3

x

+

18

Step-by-step explanation:

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