1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zubka84 [21]
3 years ago
8

1) f(x)=(x - 3)(x - 5)

Mathematics
1 answer:
NemiM [27]3 years ago
7 0

Answer:

Step-by-step explanation:

f(x)= (x - 3)(x - 5)

f(x) = x^2 - 5x - 3x + 15

f(x) = x^2 - 8x + 15

Answer is A

You might be interested in
NEED HELP PLEASE!!! Please explain your answer!
Zanzabum
             <span> You must make it a fraction by multiplying by 100, moving the decimal over by 2 spaces right so we have 36. Then, put it over 100, because it is a fraction. Now, with 36/100 we must simplify by dividing each number by another # that goes into it evenly, such as 2. We get 18/50, reduce by 2, we get 9/25. There you go hope I helped </span>
7 0
3 years ago
Read 2 more answers
What is the sum total of 2/3 + 5/10 =
sergey [27]
2•10+5•3
10•3
35/30*5 ( do it on both sides )
you'll get 7/6 or 1 1/6
8 0
3 years ago
This photo may seem normal and the guys seems happy but
azamat

Answer:

HA UR KINDA GAY

Step-by-step explanation:

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B8%7D%2B%5Csqrt%7B18%7D-%5Csqrt%7B32%7D" id="TexFormula1" title="\sqrt{8}+\sqrt{18}-\
eduard

√8+√18−√32
√2^2·2+√3^2·2−√2^4·2
√2^ 2·√2+√3^2·√2−√2^4·√2


√2 is the answer
7 0
3 years ago
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
3 years ago
Other questions:
  • Fine the volume of the prism.
    6·1 answer
  • simon makes 30 cakes he gives 1/5 of the cakes to sali he gives 10% of the 30 cakes to jane what fraction of the 30 cakes does h
    9·1 answer
  • What is the inverse of a square root?
    12·1 answer
  • If k= [-2 9 -8 7 11 6 4 4 -3] then what is -k?
    10·2 answers
  • If f(x)=4x+5 what is the value of f(-3)
    10·1 answer
  • Using the information given, select the statement that can deduce the line segments to be parallel. If there are none, then sele
    5·1 answer
  • Angles 1 and 2 are completely and congruent what is the measure of angle 1
    6·1 answer
  • Ava makes bead necklaces. She has a total of write the value of each expression.of 6,048 beads. Each necklace has 24 beads.Her f
    6·1 answer
  • I need help again<br><br><br> ‍♂️
    6·1 answer
  • One puppy weighs 12 oz another weighs 5/8 pounds which weighs more?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!