The ________ sum of squares measures the variability of the sample treatment means around the
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Answer:
Area = 32/3
Step-by-step explanation:
x = u ²
y = uv
z = 12v ²
0 ≤ u ≤ 2
0 ≤ v ≤ 1
Since ru = <2u, v, 0> and rv = <0, u, 24v>, we have
Where ru is the differentiation of x, y, z with respect to u and rv is the differentiation of x, y, z wit respect to v.
we find the cross product of ru and rv
ru × rv = 24v²i - 48uv²j + 2u²k
absolute value of ru × rv = 2u² + 24v²
We can now find the area
∫₀² du ∫₀¹ dv (2u² + 24v²) = ∫₀² du [2u²v + 8v³]₀¹ = 32/3
Detailed description can be found in the attachment
Step 1: 198 × = 66, the number of men who left the party
Step 2: 256×= 64, the number of women who left the party
66+64=130
Since 130 is the number of people that left, you would subtract it from the total number of people at the party originally.
198+256=454
454-130=325
So, 325 people are left at the party