You are right on the question
Step-by-step explanation:
Below is an attachment containing the solution.
The total interest earned is 40.75 and the final balance is 65.75
<u>Solution:</u>
Given, principle amount P = 25
Interest rate
Times compounded per year n = 12
Time in years t = 30

On substituting the values we get
![A = 25 [ 1+ \frac{0.0325}{12}]^{12\times30}= 25 [2.63]= 65.75](https://tex.z-dn.net/?f=A%20%3D%2025%20%5B%201%2B%20%5Cfrac%7B0.0325%7D%7B12%7D%5D%5E%7B12%5Ctimes30%7D%3D%2025%20%5B2.63%5D%3D%2065.75)
Interest I = A - P [since, A = P+I]

0.2(3) reoccurring.
Easiest way I can think of is to just put it in to a calculator and convert to a fraction, haha. Have fun counting up reoccurring numbers manually.
The answer is
Answer:
>OPQ,
>QPO,
>P
Step-by-step explanation:
The point, in this case the letter at the middle of the angle. , of the triangle is a name of that angle, if you put the other letters around it, the main points letter has to be in the middle once it is at the vertex of the angle.