1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Viefleur [7K]
3 years ago
8

A city’s population, P, is modeled by the function P(x) = 78,500( 1.02 )x where x represents the number of years after the year

2000.
The population of the city in the year 2000 was . The population increases by % each year. Enter your answers in the boxes.
Mathematics
1 answer:
Levart [38]3 years ago
3 0
Population 78500
Increased by 2%
You might be interested in
4/11=0.?? and please tell me how you got this answer
faltersainse [42]
4/11 is equivalent to the fraction 0.363636.... I got this answer by dividing the 4 in 11 groups, or doing the equation, 4<span>÷11</span>
8 0
2 years ago
Read 2 more answers
Parts being manufactured at a plant are supposed to weigh 65 grams. Suppose the distribution of weights has a Normal distributio
andrew-mc [135]

Answer:

0.64%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 75 grams and a standard deviation of 22 grams.

This means that \mu = 75, \sigma = 22

Sample of 144:

This means that n = 144, s = \frac{22}{\sqrt{144}} = 1.8333

More than 80 or less than 70:

Both are the same distance from the mean, so we find one probability and multiply by 2.

The probability that it is less than 70 is the pvalue of Z when X = 70. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{70 - 75}{1.8333}

Z = -2.73

Z = -2.73 has a pvalue of 0.0032

2*0.0032 = 0.0064.

0.0064*100% = 0.64%

The probability is 0.64%.

3 0
3 years ago
a construction worker brought several bottles of juice for $3 at that conventional store she paid for them with $20 bills.if j r
Alexxandr [17]
20 - 3j <== ur expression
5 0
3 years ago
XD me banearon de nuevo pero regrese igualmente no me pueden moderadores.
aleksandrvk [35]

Answer:

yeah what you said

7 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
Other questions:
  • How do you solve |x-5|<img src="https://tex.z-dn.net/?f=%5Cgeq" id="TexFormula1" title="\geq" alt="\geq" align="absmiddle" class
    9·1 answer
  • Jim wants to start investing in bonds. He checks with two brokers to ask them for suggestions of bonds to buy. Broker J, who cha
    15·2 answers
  • Can you divide the number 8,101,265,822,784 by 8 without using either long or short division?
    15·2 answers
  • Thank you so much &lt;3333
    10·1 answer
  • Write the following whole number in expanded notation.<br> 95,835
    12·1 answer
  • What equation is part of the same fact family as <br> 8 x 5 = 40
    5·1 answer
  • 4=36÷ answer please help me
    8·2 answers
  • To find the area, multiply the area of the entire circle by __?
    7·1 answer
  • work out three numbers that are in both sequences and between 20 and 40 write the numbers on a single line
    11·1 answer
  • My dog, Lilly, weighs 3.8 pounds.
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!