The solution for the problem is:Area of the box is computed by A = 2wl + 2lh + 2hw,where w - width,the l - length, and the h - height.but we need to change that, so the formula would be:A = 2 a² + 4 a h = 300 cm²h = a (the box is a cube) A = 6 a² = 300 cm²a² = 50a = 5 cmV = a³ = 5³ = 125cm³
Hello
There are quite a variety of animals that fix your explanation, but the most common one is a squirrel. A squirrel fits your description, except i'm not sure about the jumping over a river. I believe for that, it might also be a stray cat.
Answer:
C. (1.5, 5.5)
Explanation:
✔️Equation of line l in slope-intercept form, y = mx + b
y-intercept (b) = 7 (the value of y when x = 0)
Slope (m) = ∆y/∆x
Using (0, 7) and (1, 6)
Slope (m) = (6 - 7)/(1 - 0) = -1/1 = -1
Substitute m = -1 and b = 7 into y = mx + b
Equation: y = -x + 7
✔️Equation of line k in slope-intercept form, y = mx + b
y-intercept (b) = 1 (the value of y when x = 0)
Slope (m) = ∆y/∆x
Using (0, 1) and (1, 4)
Slope (m) = (4 - 1)/(1 - 0) = 3/1 = 3
Substitute m = 3 and b = 1 into y = mx + b
Equation: y = 3x + 1
✔️Solve the system of equations:
y = -x + 7 => Eqn. 1
y = 3x + 1 => Eqn. 2
Substute y = (-x + 7) in Eqn. 2
-x + 7 = 3x + 1
Collect like terms
-x - 3x = -7 + 1
-4x = -6
-4x/-4 = -6/-4
x = 1.5
Substitute x = 1.5 in eqn. 1
y = -1.5 + 7
y = 5.5
✅Solution = (1.5, 5.5)
Answer: you had never implied it had been at night, so the car itself would have been able to see the male. even if so the man was dressed in black also the car has no headlights on.
Explanation: