Pls help ! given: DR tangent to circle O. if m RDC= 150, then m DAC.<br> a. 75<br> b. 150<br> c. 300

Simplify 7 to the 6 power multpied by 7 to the 5th power

nasty-shy [4]

So... 7 to the 6th power is 7^6 =<span>117649 and multiply that with 7^5 power 16807... will give you.. </span>1977326743.. are you sure you want to multiply it? :o

6 0

3 years ago

Read 2 more answers

The dot plot shows the number of books lent by a school library during a 10-day period.

Katyanochek1 [597]

The mean absolute deviation of the number of books is 1.84

<h3>How to determine the mean absolute deviation?</h3>

The dot plot of the number of books is in the attached figure.

From the figure, we have:

x f

1 1

2 2

3 2

4 3

5 1

6 2

7 3

8 1

Start by calculating the mean using:

$\bar x= \frac{\sum fx}{\sum f}$

So, we have:

$\bar x= \frac{1 * 1 + 2 * 2 + 2 * 3 + 3 * 4 + 1 * 5 + 2 * 6 + 3 *7 + 1 * 8}{1 +2+2+3+1+2+3+1}$

Evaluate the sum and products

$\bar x= \frac{69}{15}$

Divide

$\bar x= 4.6$

The mean absolute deviation is then calculated as:

$|\bar x| = \frac{\sum f|x - \bar x|}{\sum f}$

So, we have:

$|\bar x|= \frac{1 * |1 -4.6|+ 2 * |2 -4.6| + 2 * |3 -4.6|+ 3 * |4 -4.6|+ 1 *| 5 -4.6|+ 2 * |6 -4.6|+ 3 *|7 -4.6|+ 1 * |8-4.6|}{1 +2+2+3+1+2+3+1}$

Evaluate the absolute difference

$|\bar x|= \frac{1 * 3.6+ 2 * 2.6 + 2 * 1.6+ 3 * 0.6+ 1 *0.4+ 2 * 1.4+ 3 *2.4+ 1 * 3.4}{15}$

Evaluate the sum of products

$|\bar x|= \frac{27.6}{15}$

Divide

$|\bar x|= 1.84$

Hence, the mean absolute deviation of the number of books is 1.84

Read more about mean absolute deviation at:

brainly.com/question/3250070

#SPJ1

6 0

2 years ago

I need to solve the equation please help me

lesantik [10]

Answer:

$\displaystyle x=\Big\{\frac{7\pi}{6}+2n\pi, \frac{3\pi}{2}+2n\pi, \frac{11\pi}{6}+2n\pi}\Big\}, n\in\mathbb{Z}$

Step-by-step explanation:

We are given the equation:

$4\sin^2(x)+6\sin(x)+2=0$

First, we can divide everything by 2:

$2\sin^2(x)+3\sin(x)+1=0$

Notice that we have an equation in quadratic form. Namely, if we make a substitution where u = sin(x), we acquire:

$2u^2+3u+1=0$

Solve for u. Factor:

$(2u+1)(u+1)=0$

Zero Product Property:

$2u+1=0\text{ or } u+1=0$

Solving for both cases:

$\displaystyle u=-\frac{1}{2}\text{ or } u=-1$

And by substitution:

$\displaystyle \sin(x)=-\frac{1}{2}\text{ or } \sin(x)=-1$

For the first case, recall that sin(x) is -1/2 for every 7π/6 and every 11π/6. Hence, for the first case, our solutions are:

$\displaystyle x=\frac{7\pi}{6}+2n\pi \text{ and } x=\frac{11\pi}{6}+2n\pi, n\in\mathbb{Z}$

Where n is an integer.

For the second case, sin(x) is -1 for every 3π/2. Thus:

$\displaystyle x=\frac{3\pi}{2}+2n\pi$

All together, our solutions are:

$\displaystyle x=\Big\{\frac{7\pi}{6}+2n\pi, \frac{3\pi}{2}+2n\pi, \frac{11\pi}{6}+2n\pi}\Big\}, n\in\mathbb{Z}$

4 0

2 years ago

Find the Difference: 0.325-0.01

Cerrena [4.2K]

Answer:

= 0.315

Step-by-step explanation:

hope this helps :)

3 0

2 years ago

Look at the shaded shapes drawn on a square grid.

Triss [41]

Answer:

No. Steven is not correct.

Step-by-step explanation:

The area of shape A is 15 (either multiply 5 x 3 or just count squares). The area of shape B is 9.

15 is not double 9.

4 0

2 years ago

Pls help ! given: DR tangent to circle O. if m RDC= 150, then m DAC. a. 75 b. 150 c. 300