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grandymaker [24]
3 years ago
6

Callie has a new kitten. They can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18

pounds. Find a system of equations that can be used to find the weight of each animal
Mathematics
1 answer:
gavmur [86]3 years ago
7 0

Answer:

The weight of cat is <u>14 pounds</u> and the weight of kitten is <u>4 pounds</u>.

Step-by-step explanation:

Given:

Callie has a new kitten. It can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18 pounds.

Now, to find the weight of each animal:

Let the cat's weight be x.

And the kitten weight = \frac{x}{2} -3

Total weight of cat and kitten = 18 pounds.

Now, to set an equation to get the weight of each animal:

(x)+(\frac{x}{2}-3)=18

x+\frac{x}{2} -3=18

\frac{2x+x-6}{2} =18

\frac{3x-6}{2} =18

<em>Multiplying both sides by 2 we get:</em>

<em />3x-6=36<em />

<em>Adding both sides by 6 we get:</em>

<em />3x=42<em />

<em>Dividing both sides by 3 we get:</em>

<em />x=14\ pounds.<em />

<em>The weight of cat = 14 pounds.</em>

Substituting the value of x to get the kitten's weight:

\frac{x}{2} -3\\\\=\frac{14}{2}-3\\\\=7-3\\\\=4.

<em>The kitten's weight = 4 pounds.</em>

Therefore, the weight of cat is 14 pounds and the weight of kitten is 4 pounds.

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2 years ago
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3 years ago
N a game, four cards are labeled N, S, E, and W. Two tiles are numbered 1 and 2. Two discs are red and blue. A player randomly s
algol [13]

Answer: The probability that the player selects a card with S or E, a tile with 2 and a red disc is given as 0.125 (or 1/8)

Step-by-step explanation: If four cards are labelled N, S, E and W, then that means there are a total of four possible outcomes. Also with tiles numbered 1 and 2 there are a total of two possible outcomes when selecting tiles. Then there are two discs in total (one red and one blue) which means there are a total of two outcomes when selecting discs.

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Therefore, the probability that a player selects a card with S or E is derived as follows;

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The probability that he selects a tile with 2 written on it is calculated as;

P(T2) = Number of required outcomes/Number of all possible outcomes

P(T2) = 1/2

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Therefore, the probability that the player selects a card with S or E, a tile with 2 and a red disc is calculated as;

P(S or E and T2 and R) = 0.5*0.5*0.5

P(S or E and T2 and R) = 0.125

Hence the probability that the player selects a card with S or E, a tile with 2 and a red disc is 0.125 (or 1/8).

5 0
3 years ago
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grigory [225]
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