All categories

2 years ago

Determine if the function is linear, not linear.

Mathematics

2 answers:

jekas [21]2 years ago

6 0

Answer:

y^3=x and 3y=x^2 is nonlinear while the others are linear

Viefleur [7K]2 years ago

5 0

Y^3=x and 3y=x^2 is nonlinear

the others are linear

You might be interested in

Please help me solve this :3

oksano4ka [1.4K]

Answer:

1695.6 in3 ;)

Step-by-step explanation:

8 0

3 years ago

Gulf gully and jump rope road are a pretty far distance.If the scale for the map is 0.5 inches=2.3 miles,what is the actual dist

mezya [45]

Answer:

12 cm = 21.62 miles

6 cm = 11.04 miles

Step-by-step explanation:

To find the distance, set up a proportion. A proportion is two equal ratios set equal to each other. We form the ratios by using corresponding values. We write a ratio of $\frac{map}{real world}$ and simplify.

We know $\frac{map}{real world}=\frac{0.5in}{2.3 miles}$ . We know the distance on the map is 12 cm and 6 cm whish converts to 4.7 inches and 2.4 inches. We can write $\frac{4.7in}{xmiles}$ and $\frac{2.4in}{xmiles}$

We set them equal.

$\frac{0.5}{2.3}=\frac{4.7}{x}$

and

$\frac{0.5}{2.3}=\frac{2.4}{x}$

To solve each proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

$2.3(4.7)=0.5(x)\\10.81=0.5x\\\frac{10.81}{0.5}=\frac{0.5x}{0.5} \\21.62 miles=x$

and

$2.3(2.4)=0.5(x)\\5.52=0.5x\\\frac{5.52}{0.5}=\frac{0.5x}{0.5} \\11.04 miles=x$

5 0

3 years ago

Is 1/3, 2/3, 4/3, 8/3, 16/3 arithmetic sequence

11111nata11111 [884]

The given sequence is not arithmetic sequence

Solution:

Given sequence is:

$\frac{1}{3} , \frac{2}{3} , \frac{4}{3} , \frac{8}{3} , \frac{16}{3}$

We have to find if the above sequence is arithmetic sequence or not

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

Here in the given sequence

$\text{ first term } = a_1 = \frac{1}{3}\\\\\text{ second term } = a_2 = \frac{2}{3}\\\\\text{ third term } = a_3 = \frac{4}{3}\\\\\text{ fourth term } = a_4 = \frac{8}{3}\\\\\text{ fifth term } = a_5 = \frac{16}{3}$