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natka813 [3]
2 years ago
11

Explain why the initial value of any function of the form f (x) = a(b') is equal to a.

Mathematics
1 answer:
tankabanditka [31]2 years ago
3 0

Answer:

THE ANSWER ON E2020

Step-by-step explanation: When you substitute 0 for the exponent x, the expression simplifies to a times 1, which is just a. This is because any number to the 0 power equals 1. Since the initial value is the value of the function for an input of 0, the initial value for any function of this form will always be the value of a.

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Nat2105 [25]

Answer:

Option B. Cosec θ = –5/3

Option C. Cot θ = 4/3

Option D. Cos θ = –4/5

Step-by-step explanation:

From the question given above, the following data were obtained:

Tan θ = 3/4

θ is in 3rd quadrant

Recall

Tan θ = Opposite / Adjacent

Tan θ = 3/4 = Opposite / Adjacent

Thus,

Opposite = 3

Adjacent = 4

Next, we shall determine the Hypothenus. This can be obtained as follow:

Opposite = 3

Adjacent = 4

Hypothenus =?

Hypo² = Opp² + Adj²

Hypo² = 3² + 4²

Hypo² = 9 + 16

Hypo² = 25

Take the square root of both side

Hypo = √25

Hypothenus = 5

Recall:

In the 3rd quadant, only Tan is positive.

Therefore,

Hypothenus = –5

Finally, we shall determine Sine θ, Cos θ, Cot θ and Cosec θ to determine which option is correct. This can be obtained as follow:

Opposite = 3

Adjacent = 4

Hypothenus = –5

Sine θ = Opposite / Hypothenus

Sine θ = 3/–5

Sine θ = –3/5

Cos θ = Adjacent / Hypothenus

Cos θ = 4/–5

Cos θ = –4/5

Cot θ = 1/ Tan θ

Tan θ = 3/4

Cot θ = 1 ÷ 3/4

Invert

Cot θ = 1 × 4/3

Cot θ = 4/3

Cosec θ = 1/ Sine θ

Sine θ = –3/5

Cosec θ = 1 ÷ –3/5

Invert

Cosec θ = 1 × –5/3

Cosec θ = –5/3

SUMMARY

Sine θ = –3/5

Cos θ = –4/5

Tan θ = 3/4

Cot θ = 4/3

Cosec θ = –5/3

Therefore, option B, C and D gives the correct answer to the question.

5 0
3 years ago
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