1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bekas [8.4K]
3 years ago
5

X²_50=26x

50 - 8 = 2}^{2} " alt="x { - 50 - 8 = 2}^{2} " align="absmiddle" class="latex-formula">
=3+4​
Mathematics
1 answer:
alexandr402 [8]3 years ago
3 0

Answer: yes your right

Step-by-step explanation: i used it it was right

You might be interested in
I need help As Soon As possible!
Julli [10]
This should be simple, add the Amounts of snow for the first week
4.32 + 6.86 = 11.18
-------------------------------------------------------
The subtract the amounts of snow from each week
11.18 - 7.89 = 3.29
---------------------------------------- 
C.) 3.29 is your answer
6 0
3 years ago
Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One a
Minchanka [31]

Answer:

II. One and only one solution

Step-by-step explanation:

Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.

Let assume the equation is given as;

x + 3y = 11 .... 1

x - y = -1 ....2

Using elimination method

Subtract equation 1 from 2

(x-x) + 3y-y = 11-(-1)

0+2y = 11+1

2y = 12

y = 12/2

y = 6

Substitute y = 6 into equation 2:

x-y = -1

x - 6 = -1

x = -1 + 6

x = 5

Hence the solution (x, y) is (5, 6)

<em>Hence we can say the equation has One and only one solution since we have just a value for x and y</em>

<em />

4 0
3 years ago
Help picture below problem 8
Radda [10]

Answer:

C. never

Step-by-step explanation:

A trapezoid has exactly one pair of opposite sides parallel.

A parallelogram has exactly two pairs of opposite sides parallel.

A trapezoid is never a parallelogram.

6 0
2 years ago
A group of statistics students decided to conduct a survey at their university to find the average (mean) amount of time student
Butoxors [25]

Answer: (21.541,\ 23.059)

Step-by-step explanation:

The confidence interval for population mean is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Sample size : n=240 , which is a large sample , so we apply z-test .

Sample mean : \overline{x}=22.3

Standard deviation : \sigma= 6

Significance level : \alpha=1-0.95=0.05

Critical value : z_{\alpha/2}=1.960

Now, a confidence interval at the 95% level of confidence will be :-

22.3\pm(1.960)\dfrac{6}{\sqrt{240}}\\\\\approx22.3\pm0.759\\\\=(22.3-0.759,\ 22.3+0.759)\\\\=(21.541,\ 23.059)

7 0
3 years ago
Alpha bought 4 pies, which he plans to share with a group of his friends. If there is exactly enough to give each member of the
Gnesinka [82]
There are 24 people, there are 4 pies and they each get 1/6th, 4x6=26

The entire race was 8 hours. If 3/4th of the race was 6 hours, 6/3=2 meaning 1/4th of the race is 2 hours and the full thing being 8.
6 0
3 years ago
Other questions:
  • a florist had 1006 flowers she wanted to put them into 30 bouquets with the same number of flowers in each how many more should
    7·1 answer
  • Drag and drop the constant of proportionality into the box to match the table. If the table is not proportional, drag and drop "
    13·2 answers
  • Point Q(-2, 8) is translated using the rule (x + 1, y - 2).
    5·1 answer
  • — бх - Ту = 4<br> Can y’all help me find this question
    11·1 answer
  • PLEASE ANSWER THIS WORKSHEET QUICK!
    5·1 answer
  • What is the exact value of cos 22.5°?
    6·1 answer
  • What is the slope of the line whose equation is –48 = 2x − 8y? Help Meh
    11·2 answers
  • 6 1 4 (x− 2 3 )=9 3 8
    14·2 answers
  • Help with 17,18,19,,20 and 21
    11·1 answer
  • Show that the triangles are similar by measuring the lengths of their sides and
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!