ANSWER
EXPLANATION
The given polynomials are:
and
We want to subtract these two polynomials.
Expand the right hand side to obtain:
Group the similar terms:
Combine the similar terms to get:
Brainlist for the right answer no link or bot 60 points only smart people
1 answer:
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Yes it is a function. It passes the vertical line test. In other words, it is impossible to draw a single vertical line through more than one point on the V shaped graph. Any input leads to exactly one output.
The domain is the set of all real numbers. This is because we can plug in any x value leading to some specific y value. There are no holes or gaps or jumps to indicate we must restrict any given x value. The domain would not be the set of whole numbers only because values between the whole numbers (eg: decimal values like x = 2.75) work just fine.
The range is the set of y values such that y is either 0 or larger than 0. In short, the range is
. Notice how any point on the V shaped graph has a y coordinate that is either 0 or larger than 0. It is impossible to get a y value that is negative.
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In summary,
Yes it is a function
Domain: all real numbers
Range:
So the answer is choice B
The domain is the set of all real numbers. This is because we can plug in any x value leading to some specific y value. There are no holes or gaps or jumps to indicate we must restrict any given x value. The domain would not be the set of whole numbers only because values between the whole numbers (eg: decimal values like x = 2.75) work just fine.
The range is the set of y values such that y is either 0 or larger than 0. In short, the range is
--------------------------------------------------------------------
In summary,
Yes it is a function
Domain: all real numbers
Range:
So the answer is choice B
Answer:
Step-by-step explanation:
If you have choices, you really should list them.
Here is the graph for y = (x + 0.25)(x - 1.75) which will look like yours. There are all sorts of variations that are possible, but at least I could reproduce a similar looking graph.
