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RoseWind [281]
3 years ago
15

the half-life of colbalt-60 (used in radiation therapy) is 5.26 years (actual data). How much a of 200 g sample of colbalt-60 wi

ll remain after 26.3 years? Remaining Amount = [ ? ] (1 - [ ] ) ^ [] HELP PLEASE
Mathematics
1 answer:
Oksanka [162]3 years ago
5 0

Answer:

6.25 grams

Step-by-step explanation:

Since we need to find the number of half-lives in 26.3 years, we simply divide 26.3 yrs by 5.26 yrs which yields 5 half-lives. This means that in 26.3 yrs the 200 grams of cobalt-60 will undergo 5 half-lives.

To obtain the remaining amount we simplify the expression;

A = 200*(1-0.5)^(26.3/5.26)

  = 200*(0.5)^(5)

  = 6.25 grams.

Therefore, the amount of a 200 g sample of colbalt-60 that will remain after 26.3 years is 6.25 grams

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andreyandreev [35.5K]

Answer: -2

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Draw a vertical line through 4 on the x axis. This vertical line crosses the parabola at some point (which we'll call point A). Draw a horizontal line from point A to the y axis and note how it lands on y = 12. Therefore the point (4,12) is on this parabola.

Repeat the same steps as before to find that (8,4) is also on the parabola

We need to find the slope of the line through (4,12) and (8,4)

m = (y2 - y1)/(x2 - x1)

m = (4-12)/(8 - 4)

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The slope of this line is -2 meaning that the average rate of change from x = 4 to x = 8 is -2.

The line goes down 2 units each time you move to the right 1 unit.

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3 years ago
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Black_prince [1.1K]

Answer:

x = 6

y = 9

This is the correct answer. Not satisfied? Check out this answer expert verified answer of the same question but with a step-by-step explanation. This answer is just a simple version of rocioo's correct answer.

Expert Verified Answer (of this same question but with a step-by-step explanation):

This is the link to rocioo's answer. <u>brainly.com/question/13675950</u>

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How do I fill this out? Im not sure how to?
prohojiy [21]

Answer:

z=-21

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We move all terms to the left:

(9-3)/2-((6+z)/5)=0

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We multiply all the terms by the denominator

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We calculate terms in parentheses: -((z+6)+3*5), so:

(z+6)+3*5

We add all the numbers together, and all the variables

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We get rid of parentheses

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z+21

Back to the equation:

-(z+21)

We get rid of parentheses

-z-21=0

We add all the numbers together, and all the variables

-1z-21=0

We move all terms containing z to the left, all other terms to the right

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