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Levart [38]
3 years ago
10

Help me guys it's too urgent ​

Mathematics
1 answer:
jeyben [28]3 years ago
3 0

I recommend that you download photomath, it is an app that takes a photo of the equation and answers it most of the time.

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a sailfish can go as fast as 68mph. in 1 min. can a sailfish swim as far as 1 mile? explain the answer.
Bezzdna [24]
Yes the sailfish can swim one mile
7 0
3 years ago
ZA and ZB are supplementary angles. If mZA = (x + 6) and m
Ronch [10]

Answer:

za=24

Step-by-step explanation:

supplementary angles add up to equal 180

180=7x+x+30+6

step 1 combine like terms

180=8x+36

step 2 subtract 36 from each side

144=8x

step 3 divide each side by 8

x=18

now we just plug in 18 to x in x+6

18+6=24

4 0
2 years ago
Read 2 more answers
The missing number in the series?
RoseWind [281]
A)48

Explanation:

2^3 - 2^2 = 8 - 4 = 4
3^3 - 3^2 = 27 - 9 = 18
4^3 - 4^2 = 64 - 16 = 48
5^3 - 5^2 = 125 - 25 = 100
6^3 - 6^2 = 216 - 36 = 180
7^3 - 7^2 = 343 - 49 = 294
8^3 - 8^2 = 512 - 64 = 448
7 0
3 years ago
Consider the system of equations.
frosja888 [35]

Answer:

First part: -10x-4y=-12

Second half: infinitely many solutions

Step-by-step explanation:

Just did the assignment and got it correct

6 0
3 years ago
Read 2 more answers
Triangle ABC is shown below.
Andrew [12]

Answer:

C.) 14

Step-by-step explanation:

Look at the triangle: angles b and c have the same arch, so they are congruent.

In a triangle, if two angles are congruent, then the triangle is isosceles, having two equal sides.

The sides opposite the congruent angles are congruent:

∠B → opposite side → AC

∠C → opposite side → AB

The sides AB and AC are equal. Make an equation:

AB=AC\\\\2x=3x-7

Simplify the equation, solving for x. Add 7 to both sides:

2x+7=3x-7+7\\\\2x+7=3x

Subtract 2x from both sides:

2x-2x+7=3x-2x\\\\7=x

The value of x is 7. Insert the value of x into the given length of AC:

AC=3(7)-7

Simplify multiplication:

AC=21-7

Subtract:

AC=14

Therefore, the length of the line segment AC is 14.

:Done

8 0
3 years ago
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