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Levart [38]
2 years ago
10

Help me guys it's too urgent ​

Mathematics
1 answer:
jeyben [28]2 years ago
3 0

I recommend that you download photomath, it is an app that takes a photo of the equation and answers it most of the time.

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the set below only contains which types of numbers {-1,5,1/2,15,3.75,36,square root 81,100 are they irrational numbers rational
nika2105 [10]

Answer:

I believe Irrational numbers, That's the answer I used and got it correct!

Step-by-step explanation:

5 0
3 years ago
Which points are the foci of the ellipse?
Mazyrski [523]

The foci need to be equal distances from the center of the eclipse.

See the attached picture. I marked off all the points that were given as choice and from this you can see that that (-5,-4) and  (-5,2) are both 3 units away from the center.

The answer is: (-5,-4) and  (-5,2)

7 0
2 years ago
Read 2 more answers
Plz show work and solve quick please need help!!!!!
Simora [160]
Surface area is just the area of all these 4 triangles plus the rectangle.

First we can find the area of the rectangle.

\sf A=lw

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.

\sf A=(56)(27)

\sf A=1512cm^2

The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

\sf 82.8-28=54.8\? cm

Calculate the area:

\sf A=\dfrac{1}{2}bh

\sf A=\dfrac{1}{2}(27)(54.8)

\sf A=739.8\?cm^2

We have two of these triangles.

\sf 739.8\times 2=1479.6\? cm^2

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

\sf 81.2-27=54.2\?cm

Now find the area:

\sf A=\dfrac{1}{2}bh

\sf A=\dfrac{1}{2}(56)(54.2)

\sf A=1517.6\? cm^2

We have two of these triangles.

\sf 1517.6\times 2=3035.2\?cm^2

Add all the areas together:

\sf 1512+1479.6+3035.2=\boxed{\sf 6026.80\? cm^2}
7 0
3 years ago
The equation of a circle is x^2+y^2-2x +6y-6=0. Find the center and radius of the circle by completing the square.you must inclu
zavuch27 [327]

Answer:

The center of the circle is at;

(1,-3)

The radius of the circle is;

r=4

Explanation:

Given the equation of circle;

x^2+y^2-2x+6y-6=0

we want to re-write it in the form;

(x-h)^2+(y-k)^2=r^2

where;

\begin{gathered} (h,k)\text{ is the center of the circle} \\ r\text{ is the radius} \end{gathered}

Applying Completing the square method;

\begin{gathered} x^2+y^2-2x+6y-6=0 \\ x^2-2x+1+y^2+6y+9=6+1+9 \\ (x-1)^2+(y+3)^2=16 \\ (x-1)^2+(y+3)^2=4^2 \end{gathered}

comparing the derived equation to the general form we have;

\begin{gathered} h=1 \\ k=-3 \\ r=4 \end{gathered}

Therefore;

The center of the circle is at;

(1,-3)

The radius of the circle is;

r=4

6 0
8 months ago
What is the slope of the line that passes through the points (5, -10) and (11,−12)? Write your answer in simplest form.
MA_775_DIABLO [31]

Answer:

slope=-\frac{1}{3}

Step-by-step explanation:

Use the slope formula for two points:

\frac{y(2)-y(1)}{x(2)-x(1)}=\frac{rise}{run}

Insert values

\frac{-12-(-10)}{11-5}

Simplify

\frac{-12+10}{11-5} \\\\\\\frac{-2}{6} \\\\-\frac{2}{6}

Simplify

-\frac{1}{3}

4 0
3 years ago
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