We have been given that a line $y=mx+b$ passes through the point (10, 3) and is parallel to the line $2x+5y=12$ . We are asked to find the y-intercept of the line.

First of all we will rewrite our given equation in slope-intercept form as:

$2x-2x+5y=12-2x$

$5y=-2x+12$

$\frac{5y}{5}=-\frac{2}{5}x+\frac{12}{5}$

$y=-\frac{2}{5}x+\frac{12}{5}$

We know that slope of parallel lines is equal, so slope of parallel line to our given line would be $-\frac{2}{5}$ .

Now we will use slope-intercept form of equation to find y-intercept.

$y=mx+b$ , where,

m = Slope,

b = The y-intercept.

Let us substitute $m=-\frac{2}{5}$ and coordinates of point $(10,3)$ in above equation as:

$3=-\frac{2}{5}(10)+b$

$3=-2(2)+b$

$3=-4+b$

$3+4=-4+4+b$

$7=b$

Therefore, the y-intercept is 7 and our required equation would be $y=-\frac{2}{5}x+7$ .

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=x%5E%7B8%7D%2Bx%5E%7B4%7D%2B1" id="TexFormula1" title="x^{8}+x^{4}+1" alt="x^{8}+x^{4}+1" alig

ella [17]

You did not provide directions. What do you want us to do with your 8th degree polynomial?

6 0

2 years ago

Solve for the missing information given that the two triangles in each question are similar

Mrrafil [7]

Please provide a picture or more explanation

4 0

3 years ago