. A hawk flying at a height of 60 feet spots a rabbit on the ground. If the hawk dives at a speed of 55 feet per second, how
1 answer:
Answer:
The hawk reaches the rabbit at t=4.3 sec
Step-by-step explanation:
Let
h ----> is the height in feet
t ----> is the time in seconds
v ---> the initial velocity in feet pr second
s ----- is the starting height
we have
when the hawk reaches the rabbit the value of h is equal to zero
we have
substitute
Solve the quadratic equation by graphing
The solution is t=4.3 sec
see the attached figure
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