Question

. A hawk flying at a height of 60 feet spots a rabbit on the ground. If the hawk dives at a speed of 55 feet per second, how

Answer 1

Answer:

The hawk reaches the rabbit at t=4.3 sec

Step-by-step explanation:

Let

h ----> is the height in feet

t ----> is the time in seconds

v ---> the initial velocity in feet pr second

s ----- is the starting height

we have

$h=-16t^{2} +vt+s$

when the hawk reaches the rabbit the value of h is equal to zero

we have

$v=55\ ft/sec$

$s=60\ ft$

substitute

$0=-16t^{2} +55t+60$

Solve the quadratic equation by graphing

The solution is t=4.3 sec

see the attached figure