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yawa3891 [41]
3 years ago
14

. A hawk flying at a height of 60 feet spots a rabbit on the ground. If the hawk dives at a speed of 55 feet per second, how

Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

Answer:

The hawk reaches the rabbit at t=4.3 sec

Step-by-step explanation:

Let

h ----> is the height in feet

t ----> is the time in seconds

v ---> the initial velocity in feet pr second

s ----- is the starting height

we have

h=-16t^{2} +vt+s

when the hawk reaches the rabbit the value of h is equal to zero

we have

v=55\ ft/sec

s=60\ ft

substitute

0=-16t^{2} +55t+60

Solve the quadratic equation by graphing

The solution is t=4.3 sec

see the attached figure

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