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2 years ago

6

Find the first derivative of y = sin^2(cos2x)

1 answer:

AveGali [126]2 years ago

4 0

Hello,

y=sin²(cos(2x))
y'=2*sin(cos(2x))*cos(cos(2x))*(-sin(2x)*2)
= -4*sin(cos(2x))*cos(cos(2x))*sin(2x)

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