3 years ago

Find the first derivative of y = sin^2(cos2x)

Mathematics

1 answer:

AveGali [126]3 years ago

4 0

Hello,

y=sin²(cos(2x))
y'=2*sin(cos(2x))*cos(cos(2x))*(-sin(2x)*2)
= -4*sin(cos(2x))*cos(cos(2x))*sin(2x)

You might be interested in

What’s 7^4 simplified 24 POINTS HELP QUICK AA

Blababa [14]

Answer:

2401

Step-by-step explanation:

because 7*7*7*7=2401

4 0

3 years ago

Read 2 more answers

Eight times the quantity of a number and six

andrew11 [14]

8x+6? Are you asking us to write out the equation?

5 0

3 years ago

Find the domain and range of radical function

Tju [1.3M]

The radical function is 3√x + 1.

Since the cubic root of zero is zero, 0 would be x.

Add zero and one, which gives you 1. 1 is y.

You get (0,1)

Since this is a positive radical, it would be going to the top right.

So, the domain is x ≥ 0

the range is y ≥ 1

8 0

3 years ago

1.2, 3, 7.5, 18.75, ... Which formula can be used to describe the sequence?

Nady [450]

Answer:

The formula is:

$a_n=1.2(\frac{5}{2})^{n-1}$

Step-by-step explanation:

The geometric sequences are those in which the division between the terms $a_{n + 1}$ and $a_n$ of the sequence are equal to a constant common reason called "r"

The geometrics secencias have the following form:

$a_n=a_1(r)^{n-1}$

Where $a_1$ is the first term of the sequence

In this sequence we have the following terms

1.2, 3, 7.5, 18.75

Then notice that:

$\frac{3}{1.2}=\frac{5}{2}\\\\\frac{7.5}{3}=\frac{5}{2}\\\\\frac{18.75}{7.5}=\frac{5}{2}$

Then:

$r=\frac{5}{2}$ and $a_1=1.2$

Finally the formula is:

$a_n=1.2(\frac{5}{2})^{n-1}$

5 0

3 years ago

Read 2 more answers

Which graph represents this system? 2x-5y=-5 Y=2/5x+1

zhenek [66]

both equations line up

7 0

3 years ago

Read 2 more answers