In the largest triangle, the missing side has length
√((11 + 5)² - <em>x</em> ²) = √(256 - <em>x</em> ²)
But it's also the hypotenuse of the triangle with side lengths 11 and <em>y</em>, so that its length can also be written as
√(11² + <em>y</em> ²) = √(121 + <em>y</em> ²)
so that
√(256 - <em>x</em> ²) = √(121 + <em>y</em> ²)
or, by taking the squares of both sides,
256 - <em>x</em> ² = 121 + <em>y</em> ²
<em>y</em> ² = 135 - <em>x</em> ²
In the smallest triangle, you have
5² + <em>y</em> ² = <em>x</em> ² ==> <em>x</em> ² = 25 + <em>y</em> ²
Substitute this into the previous equation and solve for <em>y</em> :
<em>y</em> ² = 135 - (25 + <em>y</em> ²)
<em>y</em> ² = 110 - <em>y</em> ²
2<em>y</em> ² = 110
<em>y</em> ² = 55
<em>y</em> = √55
Answer:
My answer:
Step-by-step explanation:
- -14K for the first blank
- -14K for the second blank
- -56 for the third blank
- 4 for the fourth blank
I multiplied -7 by 2. Then I plugged in that number to the first two blanks. Then I subtracted 21 from -35. Then I divided that number by -14.
Answer:
800+200
Step-by-step explanation:
Answer:
1. 13+10i
2. 28-(-4i)
3. -14-1i
4. 4 -i
5. 15+ 10i
6.8 - 5i^2
Step-by-step explanation:
Answer:
use the formula r = square root of (V / (pi x h))
