Evaluate the function.<br><br> g(x)=10x+3<br><br> g(19.6)=

PLEASE HELP QUICK! MARKING BRAINLYEST!

STALIN [3.7K]

The height of the tree to the nearest tenth of foot is 20.5 ft

<h3>Right angle triangle:</h3>

A right angle triangle has one of its angles as 90 degrees. The sides can be found using Pythagoras theorem.

The side of the base triangle can be found using Pythagoras theorem.

c² = a² + b²

c² = 9.2² + 5.8²

c² = 84.64 + 33.64

c = 10.9 ft

using similar triangle ratio,

5.8 / 10.9 = 10.9 / x + 5.8

5.8x = 118.81 - 33.64

x = 85.17 / 5.8

x = 14.6844827586

x = 14.7 ft

The height of the tree to the nearest foot is 14.7 + 5.8 = 20.5 ft

learn more on right angle triangle here: brainly.com/question/26909069

5 0

3 years ago

Mitch's father needs 1 and a half tons of gravel he bought 1750 pounds of gravel How many more pounds of gravel does he need??

saw5 [17]

1 and a half tons of gravel is 3000 pounds, so do 3000-1750 and get 1250 pounds of gravel.

3 0

3 years ago

Please help ill mark brainliest

lisabon 2012 [21]

Answer:

x=28

Step-by-step explanation:

3 0

3 years ago

2x+2y=8<br> X+y=4<br> Which statement is true about the solution

laila [671]

Both x and y equal 2.

2•2=4 + 2•2=4

4+4=8

2+2=4

6 0

4 years ago

Question Help Suppose that the lifetimes of light bulbs are approximately normally distributed, with a mean of 5656 hours and a

koban [17]

Answer:

a)3.438% of the light bulbs will last more than 6262 hours.

b)11.31% of the light bulbs will last 5252 hours or less.

c) 23.655% of the light bulbs are going to last between 5858 and 6262 hours.

d) 0.12% of the light bulbs will last 4646 hours or less.

Step-by-step explanation:

Normally distributed problems can be solved by the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

After we find the value of Z, we look into the z-score table and find the equivalent p-value of this score. This is the probability that a score will be LOWER than the value of X.

In this problem, we have that:

The lifetimes of light bulbs are approximately normally distributed, with a mean of 5656 hours and a standard deviation of 333.3 hours.

So $\mu = 5656, \sigma = 333.3$

(a) What proportion of light bulbs will last more than 6262 hours?

The pvalue of the z-score of $X = 6262$ is the proportion of light bulbs that will last less than 6262. Subtracting 100% by this value, we find the proportion of light bulbs that will last more than 6262 hours.