Short AnswerThere are two numbers
x1 = -0.25 + 0.9682i <<<<
answer 1x2 = - 0.25 - 0.9582i <<<<
answer 2 I take it there are two such numbers.
Let one number = x
Let one number = y
x + y = -0.5
y = - 0.5 - x (1)
xy = 1 (2)
Put equation 1 into equation 2
xy = 1
x(-0.5 - x) = 1
-0.5x - x^2 = 1 Subtract 1 from both sides.
-0.5x - x^2 - 1 = 0 Order these by powers
-x^2 - 0.5x -1 = 0 Multiply though by - 1
x^2 + 0.5x + 1 = 0 Use the quadratic formula to solve this.

a = 1
b = 0.5
c = 1

x = [-0.5 +/- sqrt(0.25 - 4)] / 2
x = [-0.5 +/- sqrt(-3.75)] / 2
x = [-0.25 +/- 0.9682i
x1 = -0.25 + 0.9682 i
x2 = -0.25 - 0.9682 i
These two are conjugates. They will add as x1 + x2 = -0.25 - 0.25 = - 0.50.
The complex parts cancel out. Getting them to multiply to 1 will be a little more difficult. I'll do that under the check.
Check(-0.25 - 0.9682i)(-0.25 + 0.9682i)
Use FOIL
F:-0.25 * -0.25 = 0.0625
O: -0.25*0.9682i
I: +0.25*0.9682i
L: -0.9682i*0.9682i = - 0.9375 i^2 = 0.9375
NoticeThe two middle terms (labled "O" and "I" ) cancel out. They are of opposite signs.
The final result is 0.9375 and 0.0625 add up to 1
Answer:
The distance between the two given complex numbers = 9
Step-by-step explanation:
<u><em>Explanation</em></u>:-
<u><em>Step(i):</em></u>-
Given Z₁ = 9 - 9 i and Z₂ = 10 -9 i
Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane
⇒ A = Z₁ = x₁ +i y₁ = 9 - 9 i and
B = Z₂ = x₂+ i y₂ = 10 -9 i
Let (x₁ , y₁) = ( 9, -9)
(x₂, y₂) = (10, -9)
<u>Step(ii)</u>:-
<em>The distance between the two points are </em>
A B = 
A B = 
AB = 
<em> AB = √81 = 9</em>
<u><em>Conclusion:-</em></u>
The distance between the two given complex numbers = 9
<u><em></em></u>
Answer: 38.25
Step-by-step explanation: You divide the whole number by the denominator in the fraction.
153/4 = 38.25
Answer:
Step-by-step explanation:
We have been given that Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. We are asked to find the volume of display box.
We know that the box is in form of cuboid, so its volume would be length times width times height.


Therefore, the volume of the display box is 216 cubic inches.