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ira [324]
3 years ago
15

Can someone plese help me count my bobux please i have 4 but i dont now how to count it all

Mathematics
1 answer:
nika2105 [10]3 years ago
7 0

Answer:

I see you are a man of culture as well

Step-by-step explanation:

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Nadusha1986 [10]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
Given cos theta = - 2/5 and sin theta &lt; 0, find the six trigonometric values. I need help with this
Lena [83]

Answer:

\sin\,\theta =-\frac{\sqrt{21} }{5}

\tan\,\theta =\frac{\sqrt{21} }{2}

\sec\,\theta = \frac{-5}{2}

cosec\,\theta =\frac{-5}{\sqrt{21} }

\cot\,\theta =\frac{2}{\sqrt{21} }

Step-by-step explanation:

\cos\theta =\frac{-2}{5}

As both sin\,\theta,

\theta lies in the third quadrant.

In the third quadrant,

\sin\theta

\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}

\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}

\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}

\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }

\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }

3 0
3 years ago
Jack works after school. Each day he is paid a set amount, plus an hourly wage. Look at the table.
lapo4ka [179]

Answer:

2.5 Plus 40 hours only because is haft hours

8 0
3 years ago
Exercise 1.2 1 Round each of these numbers to the degree of accuracy shown in brackets. a) 7765 (nearest hundred). b) 1099 (near
wlad13 [49]

Answer:

a. 700

b. 1000

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e.

6 0
2 years ago
26 over 28- 13 over 28
kkurt [141]

Answer:

13/28 (13 over 28)

Step-by-step explanation:

26/28 - 13/28 = 13/28 and since 13 is a prime number it can't be simplified

7 0
3 years ago
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