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Subduction Zones
lmk if right
It created an opportunity for the mammals to become dominant on earth by wiping out the dinosaurs.
Answer:
The water soluble hormones affect the target cells with least amount of interaction.
Explanation:
Hormones are the chemical messengers. These are the substances secreted by the endocrine glands. The hormones are secreted directly into the bloodstream and are carried to the target cells within the blood only.
Based on their structure, hormones are water-soluble or lipid-soluble. The lipid-soluble hormones are steroid hormones and thyroid hormones. These hormones can easily pass through the lipid bilayer of the cell membrane of the target cell. Therefore, the lipid-soluble hormones have intracellular receptors that are present in either cytoplasm or the nucleus of the target cells.
On the other hand, the water-soluble hormones can not pass through the lipid bilayer of the target cells. Therefore, these hormones have extracellular receptors on the surface of the target cells. Binding of the water-soluble hormones to their cell surface receptors triggers the production of the intracellular second messengers that finally carry the signal to the target protein or any other target molecule.
<u>Therefore, a water-soluble hormone exhibits the least amount of interaction with the target cell. Amine hormones such as epinephrine and melatonin, peptide hormones such as oxytocin are some examples of the water-soluble hormones. </u>
Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>
