Answer:
33
Step-by-step explanation:
Answer:
1. -12x - 9y - 6
2. -12x + 36
3. -240
4. -2
5. x = -57
6. x = -6
7. x = 48
8. x = 20
9. x = -288
10. n = 8
Step-by-step explanation:
1.
-5x - 13 + 3y - 7x - 12y + 7
-12x - 13 + 3y - 12y + 7
-12x - 6 + 3y - 12y
-12x - 6 - 9y
-12x - 9y - 6
2.
-3(4x - 12)
-3(4x) + (-3)(-12)
-12x + 36
3.
6x - 282
6(7) - 282
42 - 282
-240
4.
6x + 2(y + x)
6(-2) + 2(7 + (-2))
-12 + 2(7 - 2)
-12 + 2(5)
-12 + 10
-2
5.
x - 23 = -80
+ 23 +23
x = -57
6.
12x = -72
/12 /12
x = -6
7.
x/4 = 12
* 4 * 4
x = 48
8.
3x + 12 = 72
- 12 - 12
3x = 60
/3 /3
x = 20
9.
x/4 - 8 = -80
+ 8 + 8
x/4 = -72
* 4 * 4
x = -288
10.
-4(1 - 5n) - 8n = 92
-4 + (-4)(-5n) - 8n = 92
-4 + 20n - 8n = 92
-4 + 12n = 92
12n - 4 = 92
+ 4 + 4
12n = 96
/12 /12
n = 8
Answer:
c. (12.12, 18.48)
Step-by-step explanation:
Hello!
The study variable is X: number of times a racehorse is raced during its career.
The average number is X[bar]= 15.3 and the standard deviation is S= 6.8 obtained from a sample of n=20 horses.
To estimate the population mean you need that the variable has a normal distribution, in this case, we have no information about its distribution so I'll assume that it has a normal distribution. With n=20 the most accurate statistic to use for the estimation is a Students-t for one sample, the formula for the interval is:
X[bar] ± 

[15.3 ± 2.093 *
]
[12.12; 18.48]
Using a significance level of 95% you'd expect that the true average of times racehorses are raced during their career is included in the interval [12.12; 18.48].
I hope it helps!