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neonofarm [45]
3 years ago
13

An electrical circuit has two components in parallel. That is, the circuit works if at least one of the components works. The co

mponents work independently with probabilities 95% and 92% respectively. The chance that the circuit works is closest to
Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0

Answer:

The chances of circuit to work will be 99.6 %.

Step-by-step explanation:

The chance that the circuit will work is given by

P_{success}=1-P_{faliure}

The circuit will fail if both the components will fail

Probability of failure of component 1 is 100%-95%= 5%

Probability of faliure of component 2 is 100%-92% = 8%

Hence

P_{faliure}=(1-0.95)\times (1-0.92)\\\\P_{faliure}=0.004\\\\\therefore P_{success}=1-0.004=0.996

Thus the chances of circuit working is 99.6%

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Aggie is an Australian exchange student in China, and she currently has 14,000 yuan in her bank account. If the exchange rate ch
Evgen [1.6K]
Find the value in Australian dollars for each exchange rate. 
<span>1st exchange rate: </span>
<span>14000/6.21= $2254.43 </span>

<span>2nd exchange rate: </span>
<span>14000/6.37= $2197.80 </span>

<span>Find the difference between the two: </span>
<span>$2254.43 - $2197.80 = $56.63 </span>

Since the first value is greater than your second one Aggie lost money and your answer is <span>It decreases by $56.63.</span>
3 0
3 years ago
Solve: Six and three sevenths minus one and three sixths equals blank
Natali5045456 [20]

Answer:

4 13/16

Step-by-step explanation:

6 3/7 - 1 3/6 =

270/42  -   63/42 = 207/42 = 4 39/48 = 4 13/16

8 0
2 years ago
5d-2/3c if d =4 and c =3 evaluate fast fast
Mademuasel [1]

Answer:

2

Step-by-step explanation:

Plug 4 in for d and 3 in for c

5d-2/3c

5(4)-2/3(3)

Multiply in the numerator and the denominator

20-2/9

Subtract in the numerator

18/9

2

Hope this helps! :)

4 0
3 years ago
A train travels train travels 288 kilometre at a uniform speed. If the speed had been 4 kilometre per hour more it would have ta
kiruha [24]

Answer:

Let the speed of the train be x km/h.

Case 1:

Distance = 288 km

Speed = x km/h

Time = Distance/Speed

= 288/x h

Case 2:

Distance = 288 km

Speed = (x+4) km/h

Time = 288/x + 4 h

Since 288/x > 288/x + 4

288/x - 288/x+4 = 1

288[1/x - 1/x+4 ] = 1

[ x + 4 - x / x(x + 4) ] = 1/288

[4 / x^2 + 4x ] = 1/288

x^2 + 4x = 1152

x^2 + 4x - 1152 = 0

x^2 + 36x - 32x - 1152 = 0

x(x + 36) - 32(x + 36) = 0

(x + 36)(x - 32) = 0

x + 36 = 0 , x - 32 = 0

x = -36 , x = 32

x = -36 , rejected since speed cannot be negative.

Therefore , speed of the train = 32 km/h

4 0
3 years ago
NEED ANSWERS ASAP, 100 POINTS! There are twenty classes at each of two middle schools. The number of students in each class at e
DiKsa [7]

Note: You missed to add the dot plots chart. As I found the chart after a little research. Thus, I am attaching it and based on that dot plot chart I am solving the question which anyways would clear you concept.

Answer:

'There are about 2 more students in each class at Oak Middle School than at Poplar Middle School' is the correct statement.

Step-by-step explanation:

From the diagram, it is clear that

The data set containing Poplar Middle School:

20   20   20   21   21   21   21   21   22   22   22   22   22   22   22   23   23   23   23   24  

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

\mu = 435/20

  =\frac{87}{4}

   = 21.75

The data set containing Oak Middle School:

20   21   21   22   22   23   23   23   23   24   24   24   25   25   26   26   27   27   28   29  

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

\mu = 483/20

   =24.15

So, the difference in mean will be:

                                            24.15 - 21.75 = 2.4

Therefore, 'there are about 2 more students in each class at Oak Middle School than at Poplar Middle School' is the correct statement.

5 0
3 years ago
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