Let the prime number which does not repeat be
a, the prime number which repeats twice be
b, the prime number which repeats 3 times be
c.
Then the prime factorization of this number is
.
Let's find the prime factorization of 1000:
So let c= 5, b be a number such that b^2>2^3=8, for example let b = 3, and let a be any prime, for example 2
thus the number is
Answer: 2250
Answer:
figured it out is 25
Step-by-step explanation:
hope this helps:)
b
Step-by-step explanation:
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5/6
Steps are on paper. If need more explanation, comment