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3 years ago

Harry picks 133 apples every 7 minutes how many apples would he in 273 minutes

Mathematics

2 answers:

Viefleur [7K]3 years ago

8 0

5187 apples

explanation:
273 minutes / 7 minutes = 39 minutes
39 x 133 = 5187

irina [24]3 years ago

6 0

5187 apples to be exact and if you need me to explain why let me know

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In ΔHIJ, i = 550 inches, j = 150 inches and ∠H=92°. Find the length of h, to the nearest inch.

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Answer:575

Step-by-step explanation: deltamath

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2 years ago

For the decimal 0.09, (a) write a fraction and (b) write a percent.

sp2606 [1]

Answer:

9/100, 9%

Step-by-step explanation:

0.09 is equal to 9/100

0.09 is equal to 9 percent

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3 years ago

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Estimate the area of a polygon. A) 8 cm2 B) 10 cm2 C) 12 cm2 D) 14 cm2

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3 years ago

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a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you

aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that $P(A) = 0.8$

If you have passed subject A, the probability of passing subject B is 0.8.

This means that $P(B|A) = 0.8$

Find the probability that the student passes both subjects?

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64$

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

$p = P(A) + P(B) - P(A \cap B)$

Considering $P(B) = 0.7$ , we have that:

$p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86$

0.86 = 86% probability that the student passes at least one of the two subjects

3 0

3 years ago

Bred has to paint a wall with 8 horizontal stripes. He has enough paint only for 5 blue, 5 red and 5 white stripes. If he can us

Kay [80]

Answer:

336

Step-by-step explanation:

Required Formulas:-

1. Number of ways to select x things out of n things = ⁿCₓ

2. Number of ways to arrange n things when a things and b things are similar = n!/(a!*b!)

Since we have to choose 8 colors and we are having 3 different colors, it is only possible when we select 2 different colors (e.g. 5 red and 3 blue). To find all possible ways we will have to find all unique arrangements of selected color.

Using formula (1), number of ways to select 2 colors out of given 3 colors = ³C₂ = 3

Using formula (2), finding all unique arrangements when 5 stripes are of one color and 3 stripes are of second color = 8!/(3!*5!) = 56

Suppose, we can choose 5 stripes from red color and 3 stripes from blue color or 5 strips from blue color and 3 strips from red color. So there are 2 possibilities of arranging every 2 colors we choose .

∴ Answer=3*56*2 = 336

6 0

3 years ago