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Anestetic [448]
3 years ago
5

If I is parallel to m. Find x and y

Mathematics
2 answers:
Wewaii [24]3 years ago
6 0

Answer: make me brainlist

Step-by-step explanation: x=104

Olenka [21]3 years ago
3 0
104 ————————————————————
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Question 10 (1 point) Solve for x. 1/2+x/6=4/3
jek_recluse [69]

Answer:

The value of x for the given expression is 5 .

Step-by-step explanation:

Given expression as

\dfrac{1}{2} + \dfrac{x}{6} = \dfrac{4}{3}

Now, arrange the equation

So, \dfrac{x}{6} = \dfrac{4}{3} - \dfrac{1}{2}

<u>Taking L.C.M on right hand side </u>

Or,  \dfrac{x}{6} = \dfrac{8 -3}{6}

Or,  \dfrac{x}{6} = \dfrac{5}{6}

Or, x = \frac{5\times 6}{6}

∴  x = 5

So, The value of x = 5

Hence,The value of x for the given expression is 5 . Answer

5 0
3 years ago
Does anyone know this?
Nesterboy [21]
It's 4 units right and 3 units up :)
7 0
3 years ago
Read 2 more answers
Which expressions are equivalent when m = 1 and m = 4?
s344n2d4d5 [400]

Answer:

expression 2

Step-by-step explanation:

<h2><u>Which expressions are equivalent when m = 1 and m = 4?</u></h2>

<h3><u>first expression:</u></h3>

5m -3 and 2m + 5 + m

when m = 1

5(1) - 3 = 2  and 2(1) + 5 + 1 = 8

and m = 4

5(4) -3 =23 and  2(4) + 5 + 4 = 17

<u>expression 1 IS</u><u> NOT EQUIVALENT</u><u> </u>

<h3><u>second expression  :</u></h3>

3 m + 4 and m + 4 + 2 m

when m = 1

3 (1) + 4 = 7 and 1 + 4 +2 (1) = 7

and m = 4

3 (4) + 4 = 16 and 4 + 4 +2 (4) = 16

expression 2 <u>IS  EQUIVALENT </u>

<h3><u>third expression :</u></h3>

2 m + 7 and 3 m - 3 + m

when m = 1

2(1) + 7 = 9 and 3(1) -3 + 1 = 1

and m = 4

2(4) + 7 = 15  and 3(4) -3 + 4 = 13

expression 3 IS <u>NOT EQUIVALENT</u>

<h3><u>fourth expression :</u></h3>

5 m + 3 and 4 m + 2 + 2 m

when m = 1

5(1)+ 3 = 8  and 4(1) + 2 +2(1) = 8

and m = 4

5(4)+ 3 = 23  and 4(4) + 2 +2(4) = 26

expression 4 is <u>NOT EQUIVALENT </u>

the expression that is <u><em>EXPRESSION 2 </em></u>

8 0
3 years ago
Read 2 more answers
Can someone please help ASAP!! <br><br> Pleaseee I’ll give brainliest!!!
Grace [21]

Answer:

all real numbers

Step-by-step explanation:

The graphs of positive and negative x^2 parabolas will always have a domain of all real numbers.  Even though you only have a portion of the graph and see a "restriction" on your domain values, it is incorrect to assume that the domain is limited to what you can see.  As the branches of the parabola keep going up and up and up, the values of x keep getting bigger and bigger and bigger.  Again, this is true for all + or - parabolas.      ....... Can consider brainlist*:)

6 0
3 years ago
Read 2 more answers
Please help! I’ll give brainiest if your answer is right
mojhsa [17]

Answer:

100

Step-by-step explanation:

1_2_3_4_5_6_7_8_9_0

5 0
3 years ago
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