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Vladimir79 [104]
3 years ago
15

g Bonus: Assume that among the general pediatric population, 7 children out of every 1000 have DIPG (Diffuse Intrinsic Pontine G

lioma, an aggressive brain cancer). A pharmaceutical company designs a screening test for DIPG that has a 98% sensitivity and an 84% specificity. Given that someone has a positive test result, what is the probability they don't have DIPG
Mathematics
1 answer:
patriot [66]3 years ago
8 0

Answer:

0.9586

Step-by-step explanation:

From the information given:

7 children out of every 1000 children suffer from DIPG

A screening test designed contains 98% sensitivity & 84% specificity.

Now, from above:

The probability that the children have DIPG is:

\mathbf{P(positive) = P(positive \  |  \ DIPG) \times P(DIPG) + P(positive  \ | \  not \DIPG)\times P(not  \ DIPG)}= 0.98\imes( \dfrac{7}{1000}) + (1-0.84) \times (1 - \dfrac{7}{1000})

= (0.98 × 0.007) + 0.16( 1 - 0.007)

= 0.16574

So, the probability of not having DIPG now is:

P(not \ DIPG \  |  \ positive) = \dfrac{ P(positive  \ | \  not DIPG)\timesP(not \  DIPG)} { P(positive)}

=\dfrac{ (1-0.84)\times (1 - \dfrac{7}{1000}) }{ 0.16574}

=\dfrac{ 0.16 ( 1 - 0.007) }{0.16574}

= 0.9586

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