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Vladimir79 [104]
3 years ago
15

g Bonus: Assume that among the general pediatric population, 7 children out of every 1000 have DIPG (Diffuse Intrinsic Pontine G

lioma, an aggressive brain cancer). A pharmaceutical company designs a screening test for DIPG that has a 98% sensitivity and an 84% specificity. Given that someone has a positive test result, what is the probability they don't have DIPG
Mathematics
1 answer:
patriot [66]3 years ago
8 0

Answer:

0.9586

Step-by-step explanation:

From the information given:

7 children out of every 1000 children suffer from DIPG

A screening test designed contains 98% sensitivity & 84% specificity.

Now, from above:

The probability that the children have DIPG is:

\mathbf{P(positive) = P(positive \  |  \ DIPG) \times P(DIPG) + P(positive  \ | \  not \DIPG)\times P(not  \ DIPG)}= 0.98\imes( \dfrac{7}{1000}) + (1-0.84) \times (1 - \dfrac{7}{1000})

= (0.98 × 0.007) + 0.16( 1 - 0.007)

= 0.16574

So, the probability of not having DIPG now is:

P(not \ DIPG \  |  \ positive) = \dfrac{ P(positive  \ | \  not DIPG)\timesP(not \  DIPG)} { P(positive)}

=\dfrac{ (1-0.84)\times (1 - \dfrac{7}{1000}) }{ 0.16574}

=\dfrac{ 0.16 ( 1 - 0.007) }{0.16574}

= 0.9586

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Find the midsegment of the triangle which is parallel to CA.​
Nataliya [291]

Answer:

\pmb{ \pink{QUESTION�}}

Find the midsegment of the triangle which is parallel to CA.

\pmb{ \pink{ANSWER:-}}

Tip

  • A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
  • This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
  • If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

\frak{Explanation:-}

We have to find the segment which is parallel to CA.

From the given data,

The segment EG is the midsegment of the triangle\triangle ABC.

So we have,

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

\implies\rm{midsegment \:  EG \: parallel \: to \:  CA}

\frak{RainbowSalt}~

6 0
2 years ago
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How do you do this? Thanks for your time and effort!
V125BC [204]
Well first you have to simplify the denominators with x, by multiplying the denominator on the left times the top and bottom of the middle, and vice versa to get 10x/(4x^2-4x)-9(2x-2)/(4x^2-4x)=-1/4 and then you combine the fractions on the left to get 2(9-4x)/(4x^2-4x)=-1/4 and then you cross multiply the fractions to get 8(9-4x)=-4x^2+4x and then simplify to get 72-32x=-4x^2+4x and then 4x^2-36x+72=0 which then we can turn into 4(x-6)(x-3)=0 so x is 6 and 3
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A factory needs to produce 1,800 jars of peanut butter on a certain day.
finlep [7]

Answer:

d

Step-by-step explanation:

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7 0
2 years ago
find the measure of the arc or angle indicated. assume that lines which appear tangent are tangent
Serjik [45]

Answer:

Option (1)

Step-by-step explanation:

By the property of alternate segment theorem,

"Angle formed between the tangent and the chord in a circle measures the half of the measure of the intercepted arc"

m(∠EFG) = \frac{1}{2} × m(minor arc FG)

minor arc FG = 2m(∠EFG)

                      = 2(76°)

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Therefore, Option (1) will be the correct option.

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