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lisov135 [29]
2 years ago
14

The high temperature in a Northern City was -6 Today. The high in a Caribbean city today was +99. How much warmer was it in the

Caribbean than the Northern City?
Mathematics
1 answer:
SSSSS [86.1K]2 years ago
5 0
It was +105 degrees warmer in the Caribbean than it was in the Northern City.
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The produce market is having a sale on grapes and oranges. A customer found the following two receipts in her cart as she was wa
AleksandrR [38]

Answer:

Step-by-step explanation:

From the first receipt:

2 pounds of grapes + 4 pounds of oranges = 10.70 which, in an algebraic equation, looks like this:

2g + 4o = 10.70

From the second receipt:

3 pounds of grapes + 2 pounds of oranges = 9.65 which, in an algebraic equation, looks like this:

3g + 2o = 9.65

Putting those together into a system and solving using the elimination method:

2g + 4o = 10.7

3g + 2o = 9.65

I am going to eliminate the oranges first since it's easier to do that. I will multiply the second equation by -2 to get a new system:

2g + 4o = 10.7

-6g - 4o = -19.3

As you can see, the oranges are eliminated because 4o - 4o = 0o. That leaves us with only the grapes:

-4g = -8.6 so

g = 2.15

Grapes cost $2.15 per pound. Now sub that into either one of the original equations to solve for the cost per pound of oranges:

2(2.15) + 4o = 10.7 and

4.3 + 4o = 10.7 and

4o = 6.4 so

o = 1.60

Oranges cost $1.60 per pound. That is choice D from your list.

5 0
3 years ago
BRAINIEST TO WHOEVER RIGHT PLZ HELP
sergejj [24]

Answer:

a)  2.7 sec

b)  2.6 sec

c)  30.3 ft,  1.3 sec

Step-by-step explanation:

graphed the equation and determined answers from the curve

3 0
3 years ago
Helppp this is chemistry not math though
Scorpion4ik [409]

Answer:

It is balance she need to use. Answer is B.

7 0
3 years ago
Read 2 more answers
Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.
Hitman42 [59]
\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\

\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}

\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}

7 0
3 years ago
I need help with this please
Ierofanga [76]
C is the correct answer


we should find the area of the square and then divide it by 24.
(360/15=24)


6 \times 6 \times \pi \times  \frac{1}{24}  = 36 \times \pi \times  \frac{1}{24}   \\  = 113.04 \times  \frac{1}{24}  = 4.71



good luck
8 0
3 years ago
Read 2 more answers
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