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elena55 [62]
3 years ago
10

Find 45 divided by 5/11

Mathematics
2 answers:
Vlad [161]3 years ago
6 0
45 divided by 5 is 99
s344n2d4d5 [400]3 years ago
5 0
45 divided by 5/11 is 99
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PLEASE HELP ME !!!!​
Natalka [10]

Answer:

B

Step-by-step explanation:

There are no repeating values for x, for different values plugged in for y.

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What is the value ??????? <br> Help!
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The simplest form of StartRoot 80 EndRoot can be written as a StartRoot b EndRoot, where a = and b =
Elden [556K]

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4√5

Step-by-step explanation:

√80 = √16 times √5

√16 = 4

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6 0
3 years ago
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Tonya and Pearl each completed a separate proof to show that the alternate interior angles AKL and FLK are congruent. Who comple
Keith_Richards [23]

Answer: Pearl

Step-by-step explanation:

In step 2, she justified her step by the definition of vertical angles. However, angles AKL and GKB do not share a common side, meaning they are not adjacent angles.

4 0
2 years ago
A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?
VladimirAG [237]

Answer:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

Step-by-step explanation:

For this case we know the population deviation given by:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

4 0
3 years ago
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