1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mrac [35]
3 years ago
11

Match the polygons formed by the sets of points with their perimeters ( rounded to the nearest hundredth). Please Help me I don'

t understand this question. Thank you
A( 1, 1), B(6,13), C(8,13), D(16,-2) E(1, -2 )
38 units
K(4,2), L(8,2), M(12,5), N(6,5), O(4,4)
50 units
F(14,-10), G(16, -10), H(19,-6), I (14,-2), J(11,-6)
25.4 units
P(7,2), Q (12,2), R(12,6), S(7,10), T(4,6)
19.24 units
U(4, -1), V(12, -1), W(20,-7), X(8, -7), Y(4,-4)
Mathematics
2 answers:
MissTica3 years ago
6 0

38 units-U(4, -1), V(12, -1), W(20,-7), X(8, -7), Y(4,-4)


25.4 units-P(7,2), Q (12,2), R(12,6), S(7,10), T(4,6)


50 units-A( 1, 1), B(6,13), C(8,13), D(16,-2) E(1, -2 )


19.24 units-K(4,2), L(8,2), M(12,5), N(6,5), O(4,4)

nevsk [136]3 years ago
4 0

Answer with explanation:

→→Using the Distance formula,\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 finding the distance between two points that is between two vertices

The Points which are vertices of Polygons are

1.→ A( 1, 1), B(6,13), C(8,13), D(16,-2) E(1, -2 )

AB=\sqrt{(6-1)^2+(13-1)^2}\\\\AB=\sqrt{5^2+12^2}\\\\ AB=\sqrt{25+144}\\\\ AB=\sqrt{169}\\\\ AB=13

BC=\sqrt{(8-6)^2+(13-13)^2}\\\\ BC=\sqrt{2^2}\\\\ BC=2

CD=\sqrt{(16-8)^2+(-2-13)^2}\\\\ CD=\sqrt{8^2+15^2}\\\\CD=\sqrt{64+225}\\\\CD=\sqrt{289}\\\\CD=17\\\\DE=\sqrt{(16-1)^2+(-2+2)^2}\\\\DE=\sqrt{15^2}\\\\DE=15 \\\\AE=\sqrt{(1-1)^2+(-2-1)^2}\\\\ AE=\sqrt{3^2}\\\\ AE=3

→→AB+BC+CD+DE+EA= 13+2+17+15+3

         =50 units

2. K(4,2), L(8,2), M(12,5), N(6,5), O(4,4)

KL=\sqrt{(8-4)^2+(2-2)^2}=\sqrt{4^2}=4\\\\ LM=\sqrt{(8-12)^2+(2-5)^2}=\sqrt{4^2+3^2}=\sqrt{5^2}=5\\\\MN=\sqrt{(12-6)^2+(5-5)^2}=\sqrt{6^2}=6\\\\NO=\sqrt{(6-4)^2+(5-4)^2}=\sqrt{2^2+1^2}=\sqrt{5}\\\\KO=\sqrt{(4-4)^2+(4-2)^2}=\sqrt{2^2}=2

→KL+LM+MN+NO+OK=4+5+6+√5+2

                                 =17+2.24

                                 = 19.24 units

3. F(14,-10), G(16, -10), H(19,-6), I (14,-2), J(11,-6)

FG=\sqrt{(16-14)^2+(-10+10)^2}=\sqrt{2^2}=2\\\\ GH=\sqrt{(19-16)^2+(-6+10)^2}=\sqrt{4^2+3^2}=\sqrt{5^2}=5\\\\HI=\sqrt{(19-14)^2+(-6+2)^2}=\sqrt{5^2+4^2}=\sqrt{25+16}=\sqrt{41}\\\\IJ=\sqrt{(14-11)^2+(-2+6)^2}=\sqrt{3^2+4^2}=\sqrt{5^2}=5\\\\JF=\sqrt{(14-11)^2+(-10+6)^2}=\sqrt{3^2+4^2}=\sqrt{5^2}=5

→FG+GH+HI+IJ+JF=2+5+√41+5+5=19+6.40=25.40

4.→ P(7,2), Q (12,2), R(12,6), S(7,10), T(4,6)

 PQ=\sqrt{(12-7)^2+(2-2)^2}=\sqrt{5^2}=5\\\\ QR=\sqrt{(12-12)^2+(-6+2)^2}=\sqrt{4^2+0^2}=\sqrt{4^2}=4\\\\RS=\sqrt{(12-7)^2+(-6+10)^2}=\sqrt{5^2+4^2}=\sqrt{25+16}=\sqrt{41}\\\\ST=\sqrt{(7-4)^2+(-10+6)^2}=\sqrt{3^2+4^2}=\sqrt{5^2}=5\\\\PT=\sqrt{(7-4)^2+(-2+6)^2}=\sqrt{3^2+4^2}=\sqrt{5^2}=5

PQ+QR+RS+ST+TP=5+4+√41+5+5

                              =19+6.40

                              = 25.40 units

5.→U(4, -1), V(12, -1), W(20,-7), X(8, -7), Y(4,-4)

UV=\sqrt{(12-4)^2+(-1+1)^2}=\sqrt{8^2}=8\\\\ VW=\sqrt{(20-12)^2+(-7+1)^2}=\sqrt{8^2+6^2}=\sqrt{64+36}=\sqrt{100}=10\\\\WX=\sqrt{(20-8)^2+(-7+7)^2}=\sqrt{12^2+0^2}=12\\\\XY=\sqrt{(8-4)^2+(-7+4)^2}=\sqrt{3^2+4^2}=\sqrt{5^2}=5\\\\YU=\sqrt{(4-4)^2+(-4+1)^2}=\sqrt{3^2+0^2}=\sqrt{3^2}=3

UV +V W+W X+XY+YU

      = 8+10+12+5+3

       =38 units

You might be interested in
3/8 divided by 13/16
dedylja [7]

Answer:

Fraction= 6/13

Decimal= 0.4615

8 0
3 years ago
Read 2 more answers
Pls say hard very hard​
Simora [160]

(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.

(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?

On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:

50 ≤ score ≤ 60   ==>   50-60

60 < score ≤ 70   ==>   60-70

70 < score ≤ 80   ==>   70-80

80 < score ≤ 90   ==>   80-90

90 < score ≤ 100   ==>   90-100

Then a student who scored a 60 should be added to the 50-60 category.

8 0
2 years ago
If f(x) and f -1 (x) are inverse functions of each other and f(x) = 2x+5, what is f -1 (8)?
Aleksandr [31]

Answer: 3/2

Step-by-step explanation:

The first one: y=2x+5

X=2y+5.Then solve for y after switching x and y

X-5=2y, X-5/2=y

Since F-1= X-5/ 2, we plug the value of X in

8-5/2, so it should be 3/2

5 0
3 years ago
(-6, 1) and 3, 5)<br> M= rise/run=(y2-y1)/(x2-x1)
Sergeeva-Olga [200]

Answer:

4/9

Step-by-step explanation:

The slope of these points would be: (5-1)/(3+6) = 4/9

7 0
3 years ago
How many 3-digit natural numbers are there?
Aleks04 [339]

Answer:

900

Step-by-step explanation:

natural numbers are all positive numbers that dont include 0

5 0
3 years ago
Other questions:
  • Find the amount in a account where $200 is invested at 3.5% compounded quarterly for a period of 3 years.
    11·1 answer
  • I have no idea what to do
    13·1 answer
  • Which one is greater 7/8 or 2/8
    12·2 answers
  • Vera is using her phone.Its battery life is down to 2/5,and it drains another 1/9 every other. How many hours will her battery l
    9·2 answers
  • 16% of what equals 44?
    5·1 answer
  • What is the equation of a horizontal line that passes through the point (-3, 4)?
    8·2 answers
  • Help I need to turn this in 15mins
    9·1 answer
  • Could someone help me on question 1<br><br>thx
    13·1 answer
  • <img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B4a%20%7B%7D%5E%7B6%7D%20%7D%20%20%5C%3A%20%20%2B%20%20%5Cfrac%7B2%7D%7Ba%2
    8·1 answer
  • Hi can someone please help
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!