B. Nanoscale
Because Nano- mean small and you’re measuring something on a ‘scale’
I think the answer is <span>supersaturated</span>
Answer is: her reasoning is flawed, because <span>Kc is very small, so the concentration of nitric(II) oxide is also very small. </span>
Balanced chemical reaction: N₂(g) + O₂(g) ⇄<span> 2NO(g).
</span>The equilibrium
constant<span> (Kc) is
a ratio of the concentration of the products (in this reaction nitrogen(II) oxide) to the concentration of the reactants (in this reaction nitrogen and oxygen):
</span>Kc = [NO]² / [N₂] · [O₂].
Kc = 4.7·10⁻³¹.
If we take equilibrium concentration of oxygen and nitrogen to be 1 M:
[N₂] = [O₂] = 1 M.
[NO] = √[N₂] · [O₂] · Kc.
[NO] = 6.855·10⁻¹⁶ M; equilibrium concentration of nitric oxide.
Answer:
<u><em>A. They don't form compounds</em></u>
Explanation:
- High density: The strong bonding between the atoms in transition metals cause them to be tightly held together, creating a high density. Colored compounds: Transition metals tend to form more colored compounds than other elements, either in solid form or dissolved in a solvent.
Answer:
16.8dm3
Explanation:
2 moles of CO gives 1 mole of N2
2 moles of CO= 2* 28= 56g
1 mole of N2 = 1* 22.4dm
56g of CO gives 22.4dm3 of N2
42.7 of CO will give> (42.7*22.4)/56
=16.8dm3
