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777dan777 [17]
4 years ago
7

Combustion analysis of an unknown compound provides the following data: 73.5 grams C, 4.20 grams H, and 72.3 grams Cl. What is t

he percent composition of each element in this compound? 73.5% C, 4.20% H, 72.3% Cl 48.0% C, 3.00% H, 50.0% Cl 17.5% C, 1.00% H, 17.2% Cl 49.0% C, 2.80% H, 48.2% Cl
Chemistry
1 answer:
tino4ka555 [31]4 years ago
8 0
The  %  composition  of  each  element  is  calculated  as   follows

=  mass   of  the  element/total  mass   x100

total  mass=  73.5+4.2+72.3=150
%  composition  of  C  =  73.5/150 x100=49%

%  composition  of  H= 4.2/150 x100=  2.8%

%composition  of  Cl=  72.3/150  x100=  48.2%
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Putting values in above equation, we get:

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Putting values in above equation, we get:

83=\frac{\text{Actual yield of carbon dioxide}}{57.2}\times 100\\\\\text{Actual yield of carbon dioxide}=\frac{57.2\times 83}{100}=47.48g

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7 0
3 years ago
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Answer:

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Explanation:

To calculate the freezing point of a water solution of fructose,

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2. calculate the number of moles of fructose in the solution

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5. the freezing point is therefore

0.00 ◦C - 4.70 ◦C = -4.70 ◦C

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