Answer:
1.8321 kg
Explanation:
The given 1 kg of coal contains 50% of the carbon atom by mass. Thus, mass of carbon in coal is 
Also, 1 kg = 1000 g
So, mass of carbon = 500 g
The formula for the calculation of moles is shown below:
Molar mass of carbon = 12.0107 g/mol
Moles of methanol = 500 g / 12.0107 g/mol = 41.6295 moles
Considering the reaction:
From the reaction,
1 mole of C react to form 1 mole of 
So,
41.6295 moles of C react to form 41.6295 moles of
Moles of = 41.6295 moles
Molar mass of = 44.01 g/mol
So, Mass = Moles × Molar mass = 41.6295 moles × 44.01 g/mol = 1832.1143 g
Also, 1g = 0.001 kg
<u>So, amount of released = 1.8321 kg</u>
Answer:
Lead Pb
Explanation:
Firstly, we need to know what occurs when a radioisotope emits an alpha particle. An alpha particle is an helium atom. When an isotope emits an alpha particle, it loses an helium atom corresponding to subtracting 4 from its mass number and 2 from its atomic number. This of course coupled with the release of radiation.
Now, we polonium has a proton number of 84 and a mass number of 210. Subtracting 2 and 4 respectively from its proton and mass numbers will yield 82 and 206 proton and mass numbers respectively.
Hence, the decomposition of the Po-210 isotope will yield an element with 82 proton number and 206 mass number. This corresponds to the element Lead.
210Po ——> 206Pb + alpha particle + radiation
Answer:
Change in temperature of calorimeter is 
Explanation:
Molar mass of anethole = 148.2 g/mol
So, 0.950 g of anethole = 
of anethole = 0.00641 moles of anethole
1 mol of anethole releases 5541 kJ of heat upon combustion
So, 0.00641 moles of anethole release 
of heat or 35.52 kJ of heat
7.854 kJ of heat increases 
temperature of calorimeter.
So, 35.52 kJ of heat increases 
or temperature of calorimeter
So, change in temperature of calorimeter is
First, since l = n-1,
5,4,-5,1/2 and 2,1,0,1/2 are the only answer choices left.
Next, since ml = -l to l,
2,1,0,1/2
is the answer because in 5,4,-5,1/2, the ml value of -5 is not in the range of -4 to 4, as notes by the value 4 for l.
Answer:
Q = 9460 Kj
Explanation:
Given data:
Mass of copper = 2kg
Latent heat of vaporization = 4730 Kj/Kg
Energy required to vaporize 2kg copper = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram copper is 4730 Kj thus, for 2 kg
by putting values,
Q= 2kg × 4730 Kj/Kg
Q = 9460 Kj
