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sattari [20]
3 years ago
14

The equation below specifies a function. Determine whether the function is​ linear, constant, or neither.

Mathematics
2 answers:
saveliy_v [14]3 years ago
8 0

Answer:

Linear function is specified by the equation ⇒ answer B

Step-by-step explanation:

* Look to the attached file

Download docx
Solnce55 [7]3 years ago
4 0

Answer:

B . Linear function.

Step-by-step explanation:

3x + 4y = 1

The degree of x and y is  1 and

if we drew a graph of this function we get a straight line.

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What is the value of the expression 3a+b2 when a=14 and b=32 ?
soldi70 [24.7K]

Answer:

106

Explanation:

3a+b2

Substitute the values for the variables:

3(14) + 2(32)

Solve:

3(14) + 2(32)

42 + 64

106

5 0
3 years ago
The figure consists of a quarter circle and a parallelogram. What is the area of the composite figure? Use 3.14 for pi. Round to
Andru [333]
The area of a full circle is given by
  A = π*r^2
so the area of a 1/4 circle will be 1/4 of that:
  A = (π/4)*r^2

The area of a parallelogram is the product of base length and height:
  A = bh

Your composite figure will have an area that is the sum of the areas of the parts.
  A = (quarter circle area) + (parallelogram area)
  A ≈ (3.14/4)*(14 in)^2 +(14 in)*(5 in)
  A ≈ 223.86 in^2 ≈ 224 in^2

The most appropriate selection is the last one,
  224 in^2
7 0
3 years ago
Read 2 more answers
In a hand of playing cards, what is the probability that all five are of the same suit?
amid [387]

Answer:

How many five-card hands dealt from a standard deck of 52 playing cards are all of the same suit? If a random hand is dealt, what is the probability that it will have this property?

Would the probability be:

(135)∗(41)(525)

3 0
3 years ago
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The value of y varies directly with x. If x=3, then y=21. What is the value of x when y=105?
Aneli [31]

21/7 = 3 so then, 105/7 = x which is 15

3 0
3 years ago
Please help me with my question<br> Thank you <br> :))BRAINLIEST AVAILABLE
lara [203]
P=4πlr²
r²=P/4πl
r=√(P/4πl)= 1/2*(√(P/πl)
Answer is A
4 0
3 years ago
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