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belka [17]
3 years ago
8

290 pennies are equal to how many dimes

Mathematics
2 answers:
ExtremeBDS [4]3 years ago
6 0
29 dimes
............
Delicious77 [7]3 years ago
4 0
29 dimes because 10 times 29 equals 290
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Factor this expression 27x+15y-9
Svet_ta [14]
Factor the following:
27 x + 15 y - 9

Factor 3 out of 27 x + 15 y - 9:

Answer:  3 (9 x + 5 y - 3)
6 0
3 years ago
192=6000(.02(8/5-4Y)+.08y)<br> solve for y
Katena32 [7]

Given:

The equation is:

192=6000\left(0.02\left(\dfrac{8}{5}-4y\right)+0.08y\right)

To find:

The value of y.

Solution:

We have,

192=6000\left(0.02\left(\dfrac{8}{5}-4y\right)+0.08y\right)

On simplification, we get

192=6000\left(0.02\times 1.6-0.02\times 4y+0.08y\right)

192=6000\left(0.032-0.08y+0.08y\right)

192=6000\left(0.032\right)

192=192

Since LHS=RHS and the equation is free from the variable y, therefore the given equation is true for all real values of y.

Hence, all real values of y are solutions.

7 0
3 years ago
Simplify the following square root √ -1 =​
quester [9]

Answer:

1 .

because sqare root of -1= 1

3 0
3 years ago
Read 2 more answers
Hi! Hope You're Having A More Than Amazing Day!
SCORPION-xisa [38]

890 is the answer hope I got it

3 0
3 years ago
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Godfrey plays a game in which he throws two fair six sided dice. If he rolls two sizes, he wins 20p, if he rolls one six, he win
blagie [28]

Answer:

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Step-by-step explanation:

If random variable X represents the amount Godfrey gains in one turn.

There are 3 different possible outcomes for X.

- Godfrey pays 5p to enter the game and gets two sixes and wins 20p.

Net gain = 15p

Probability of getting two sixes from two fair dice

= (number of outcomes with two sixes) ÷ (total number of outcomes)

number of outcomes with two sixes = 1

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (1/36) = 0.0278

- Godfrey pays 5p to enter the game and gets only one six and wins 10p.

Net gain = 5p

Probability of getting one six from either of two fair dice

= (number of outcomes with one six) ÷ (total number of outcomes)

number of outcomes with one six = 2 × n[(6,1), (6,2), (6,3), (6,4), (6,5)] = 2 × 5 = 10

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (10/36) = 0.278

- Godfrey pays 5p to enter the game and doesn't win anything

Net gain = -5p

Probability of not getting two sixes or one six.

= 1 - [(Probability of getting two sixes) + (Probability of getting one six on.wither dice)]

= 1 - 0.0278 - 0.278 = 0.6942

Probability of getting not getting two sixes or one six = 0.6942

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Hope this Helps!!!

4 0
3 years ago
Read 2 more answers
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