Question

Find the restrictions on the variable.

Answer 1

Answer:

$\frac{x-5}{x+1}$, $x\neq -1, x\neq -9$

Step-by-step explanation:

x^2 + 4x - 45

= (x+9)(x-5)

x^2 + 10x + 9

= (x+9)(x+1)

So the fraction goes to

$\frac{(x+9)(x-5)}{(x+9)(x+1)}$ which is $\frac{x-5}{x+1}$.

Since the denominator cannot be 0, x^2 + 10x + 9 cannot be equal to 0. Therefore x cannot be -1 or -9.