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iren2701 [21]
3 years ago
9

Find the restrictions on the variable.

Mathematics
1 answer:
stiv31 [10]3 years ago
7 0

Answer:

\frac{x-5}{x+1}, x\neq -1, x\neq -9

Step-by-step explanation:

x^2 + 4x - 45

= (x+9)(x-5)

x^2 + 10x + 9

= (x+9)(x+1)

So the fraction goes to

\frac{(x+9)(x-5)}{(x+9)(x+1)} which is \frac{x-5}{x+1}.

Since the denominator cannot be 0, x^2 + 10x + 9 cannot be equal to 0. Therefore x cannot be -1 or -9.

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