Answer18:
The quadrilateral ABCD is not a parallelogram
Answer19:
The quadrilateral ABCD is a parallelogram
Step-by-step explanation:
For question 18:
Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope is 90 degree
The slope of a line BC:
m=
m=
m=
The slope is zero degree
The slope of a line CD:
m=
m=
m=
The slope is 90 degree
The slope of a line DA:
m=
m=
m=
m=
The slope of the only line AB and CD are the same.
Thus, The quadrilateral ABCD is not a parallelogram
For question 19:
Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope of a line BC:
m=
m=
m=
m=3
The slope of a line CD:
m=
m=
m=
The slope of a line DA:
m=
m=
m=3
The slope of the line AB and CD are the same
The slope of the line BC and DA are the same
Thus, The quadrilateral ABCD is a parallelogram
Answer:
x = 4
Step-by-step explanation:
12/15=28/a which is a=35
then 35+28=63
14x+7=63 and x would be 4
Answer:
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Answer:
im sorry im not going to read all that because i really dont like reading so im sorry :(
Step-by-step explanation:
Answer:
5.7 units
Step-by-step explanation:
The distance from point P to QS is the distance from point P (1, 1) to the point of interception R(-3, 5).
Use distance formula to calculate distance between P and R:

Let,


Plug in the values into the formula.




(to nearest tenth)