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Mashcka [7]
3 years ago
13

Which of the following expressions is a sixth root of unity?

Mathematics
2 answers:
sukhopar [10]3 years ago
8 0
-1 for apex i just answered this question and got it right

Dima020 [189]3 years ago
3 0

Let sixth root of unity be x

So x^{6}=1

x^6-1=0

(x^3)^2-1^2=0

(x^3-1)(x^3+1)=0x^3-1=0  $ or $ x^3+1=0

(x-1)(x^2+x+1)=0 $ or $ (x+1)(x^2-x+1)=0x-1=0 $ or $ x^2+x+1=0 $ or $ x+1=0 $ or $ x^2-x+1=0

Using Quadratic formula for the quadratic equations we get

x=1 $ or $ x=\frac{-1\pm\sqrt{1-4} }{2}   $ or $ x = -1 $ or $  x=\frac{1\pm\sqrt{1-4} }{2}

x = 1 $ or $ x=\frac{-1\pm\sqrt{3}i }{2} $ or $ x = -1 $ or $ x=\frac{1\pm\sqrt{3}i }{2}

Only 1, out of the given option is the sixth root of unity.

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g(x) = (1/4)x^2 . correct option C) .

<u>Step-by-step explanation:</u>

Here we have , f(x)=x^2  and we need to find g(x) from the graph . Let's find out:

We have ,  f(x)=x^2   . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !

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