Given: ΔPSQ, PS = SQ Perimeter of ΔPSQ = 50 SQ – PQ = 1 Find: Area of ΔPSQ
1 answer:
Answer:
120 units²
Step-by-step explanation:
Perimeter = PS + SQ + PQ
50 = SQ + SQ + (SQ -1)
51 = 3SQ
17 = SQ
17 -1 = 16 = PQ
The midpoint of the base is one leg of the right triangle whose other leg is the height of this isosceles triangle. That height is ...
h = √(17² -(16/2)²) = √225 = 15
Then the area is ...
A = (1/2)bh = (1/2)(16)(15) = 120 . . . . . square units
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