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iogann1982 [59]
3 years ago
14

Given: ΔPSQ, PS = SQ Perimeter of ΔPSQ = 50 SQ – PQ = 1 Find: Area of ΔPSQ

Mathematics
1 answer:
Lana71 [14]3 years ago
8 0

Answer:

  120 units²

Step-by-step explanation:

Perimeter = PS + SQ + PQ

50 = SQ + SQ + (SQ -1)

51 = 3SQ

17 = SQ

17 -1 = 16 = PQ

The midpoint of the base is one leg of the right triangle whose other leg is the height of this isosceles triangle. That height is ...

  h = √(17² -(16/2)²) = √225 = 15

Then the area is ...

  A = (1/2)bh = (1/2)(16)(15) = 120 . . . . . square units

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