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2 years ago

Can someone answer plz

Mathematics

1 answer:

NeX [460]2 years ago

3 0

1.D 2. A 3.C 4.D

1 Is the monomial as it only contains one expression.

2. Is the difference of squares because something squared minus something squared.

3. Is standard because it is of the form

$a_nx^n+ a_{n-1}x^{n-1}+...+a_1x+a_0$

4. We know D is the not the monomial simply because its power is negative which means it does not fit the definition of a polynomial.

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I need help asap someone please help me i dont understand this question so can someone help me

eduard

Answer:

we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

Step-by-step explanation:

Given the expression

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}$

$=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}$

cancel the common factor: 2

$=\frac{p\left(2p+1\right)}{\left(4p^2-1\right)p^3}$

cancel the common factor: p

$=\frac{2p+1}{p^2\left(4p^2-1\right)}$

$=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}$

cancel the common factor: 2p+1

$=\frac{1}{p^2\left(2p-1\right)}$

Expanding

$=\frac{1}{2p^3-p^2}$

Thus, we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

7 0

2 years ago

$600 invested with compound interest at a rate of 4% per year for 10 years <br> formula:M= P(1+i)^n

makkiz [27]

Answer: M = 2100$

Explanation:

M = P(1 + I)^n

P = 600$, I = 4% = 0.04, n = 10

=> M = 600(1 + 0.04)^10
M = 600(1.04)^10
M = 600(3.5)
M = 2100$

8 0

2 years ago

Find the value of x.

ella [17]

Answer:

502.4

Step-by-step explanation:

Use tangent because the side you know and the side with x are both legs.

Do 203/tan(22) and you should get your awnser.

You devide by 203 because the rule is opposite over ajacent and 203 is the opposite side.

4 0

2 years ago

If e || f and a || b, what is the value of y. *

Blizzard [7]

Answer:

y = 90

Step-by-step explanation:

Since, e || f and a || b

Therefore, quadrilateral so formed is a rectangle.

Each angle of a rectangle is right angle.

$\therefore \: y \degree = 90 \degree \\ \\ \huge \red{ \boxed{ \therefore \: y = 90}} \\ \\$

3 0

3 years ago

David was thinking of a number. David doubles it and adds 2.9 to get an answer of 13.2. Form an equation with

Ivenika [448]

Answer:

x2+2.9=13.2

Step-by-step explanation:

4 0

2 years ago