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LenKa [72]
3 years ago
6

What does it mean when you need to graph a piecewise function where f(x) =0 if x is not an integer

Mathematics
1 answer:
ruslelena [56]3 years ago
7 0
It means that the graph is discontinuous. It consists of a line that looks like the x axis, but at every integer value of x there will be a hole. The piecewise function will probably contain f(x)=1 or some other function for x equal to an integer. This other function will also be discontinuous because it will consist of isolated points separated by gaps.

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What can you conclude about the population density from the table provided? Population Area (km²) Region A 20,178 521 Region B 1
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Answer:

A got it right

Step-by-step explanation:

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Question 4 of 10, Step 1 of 1 1/out of 10 Correct Certify Completion Icon Tries remaining:0 The Magazine Mass Marketing Company
erastovalidia [21]

Answer:

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

Step-by-step explanation:

For each entry form, there are only two possible outcomes. Either it includes an order, or it does not. The probability of an entry including an order is independent of any other entry, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes.

This means that n = 16

They know that the probability of receiving a magazine subscription order with an entry form is 0.5.

This means that p = 0.5

What is the probability that no more than 3 of the entry forms will include an order?

At most 3 including an order, which is:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{16,0}.(0.5)^{0}.(0.5)^{16} \approx 0

P(X = 1) = C_{16,1}.(0.5)^{1}.(0.5)^{15} = 0.0002

P(X = 2) = C_{16,2}.(0.5)^{2}.(0.5)^{14} = 0.0018

P(X = 3) = C_{16,3}.(0.5)^{3}.(0.5)^{13} = 0.0085

Then

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0002 + 0.0018 + 0.0085 = 0.0105

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

6 0
3 years ago
Simply the following expression: 8x + 5y - 4z + 9y - 3x + 13z
oksian1 [2.3K]

Answer:

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Step-by-step explanation:

combine 8x and -3x to get 5x

combine 5y and 9y to get 13y

combine -4z and 13z to get 9z

7 0
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