Answer:
Paco will have 335 dollars available for the car-loan
Explanation:
fromthe $490 cash flow
we should subtract the cash cost as once we obtain it through a loan we will have to handle with them as well:
490
- 60 gas
- 70 insurance
- 15 maintenance
<u> - 10 repairs </u>
335 net monthly savings after the purchase of the car.
Answer:
<u>Scholarship Amount would be $45.68</u>
Explanation:
Deposits into an endowment account that pays 12% per year
Year 0 Deposit $100
Year 1 Deposit $90
Year 2 Deposit $80
Year 3 Deposit $70
Year 4 Deposit $60
Year 5 Deposit $50
Year 6 Deposit $40
First find the present worth of the gradient deposits.
P = 100 + 90(P/A, 12%, 6) - 10(P/G, 12%, 6) = $380.69
A = 380.69 (0.12)
A= $45.68
Answer:
$13,290.89 and $15,734.26
Explanation:
In this question we have to use the Present value function which is shown on the attachment below:
In the first case
Provided that
Future value = $0
Rate of interest = 12% ÷ 12 months = 1%
NPER = 48 months
PMT = $350
The formula is shown below:
= PV(Rate;NPER;PMT;FV;type)
So, after solving this, the present value is $13,290.89
In the second case
Provided that
Future value = $0
Rate of interest = 12% ÷ 12 months = 1%
NPER = 60 months
PMT = $350
The formula is shown below:
= PV(Rate;NPER;PMT;FV;type)
So, after solving this, the present value is $15,734.26