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Sveta_85 [38]
3 years ago
7

(5b^3 +9b+4)−(9b−4) Subtract. standard form

Mathematics
1 answer:
Luda [366]3 years ago
4 0

Answer:

the answer is 5b^3+8

Step-by-step explanation:

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Please help me with 1 and 2 and show me how you get it and the answers
FromTheMoon [43]

Step-by-step explanation:

1. a²=25²-15²

a²=(25-15)(25+15)

a²=10×40

a=20

2.b²=10²-6²

b²=(10-6) ×(10+6)

b²=4×16

b=8

6 0
3 years ago
Yolanda has $38 in a bank account. she wants to make two equal deposit so that her account will have a balance of $100. how much
Tems11 [23]
<em>$38 in Yolanda's bank account.</em>
<em>She makes two equal deposits so her account has a balance of $100.</em>

If Yolanda makes two equal deposits so her account has a balance of $100, she would have made a deposit of $31 each.

38+31+31=100
4 0
3 years ago
Read 2 more answers
H(x)=-3x-4 What is g(6)
mrs_skeptik [129]

Answer:

h(6)=-22

Step-by-step explanation:

h(x)=-3x-4

h(6)=-3(6)-4

h(6)=-18-4

h(6)=-22

6 0
4 years ago
Find the solution(s) for x in the equation below. x^2 + 10x + 21= 0
Law Incorporation [45]

The solutions for ‘x’ in the given equation are – 3  and  - 7

<u>Step-by-step explanation:</u>

Given equation:

                   x^{2} + 10 x + 21 = 0

To find the ‘x’ value, try to factor, because in this case it works, it's fast. By using factor method, we get

                    (x + 3) (x + 7) = 0  (adding both value we get 10 and multiply as 21 as in equation and check with signs also while factoring)

                     x = - 3, -7

Verify above values by multiply both terms,

                     (x + 3) (x + 7) = 0

                x^{2} + 7 x + 3 x + 21 = 0

                x^{2} + 10 x + 21 = 0 (so values obtained from factor method are correct)

Or, can use quadratic formula, for a x^{2} + b x + c=0, the solutions are given by:

                      x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In the given equation, a = 1, b = 10, c = 21, apply these in above formula

                     x=\frac{-10 \pm \sqrt{10^{2}-(4 \times 1 \times 21)}}{2(1)}=\frac{-10 \pm \sqrt{100-84}}{2}

                     x=\frac{-10 \pm \sqrt{16}}{2}=\frac{-10 \pm 4}{2}

So,

When  x=\frac{-10+4}{2}=\frac{-6}{2}=-3

When x=\frac{-10-4}{2}=\frac{-14}{2}=-7

Hence, the values for ‘x’ are - 3 and - 7

7 0
3 years ago
Please help me literally need this to be answered in 2 hours P-L-E-A-S-E !!
Sonja [21]

Answer:

Yeah with that type of problem

Step-by-step explanation:

You aint getting answered for the next 4 hours <3

6 0
3 years ago
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